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GPAT Physical Chemistry Flashcards

56 question-and-answer cards covering Physical Chemistry as it is examined in GPAT. 24 of them are printed below, taken from across the deck — no signup, no paywall on the preview.

56Cards in deck
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8Syllabus topics
~123Chars per answer
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24 sample cards from the Physical Chemistry deck

Sampled from the end of the deck, so these are different cards from the ones shown on the syllabus page.

  1. State the rate law expression for a general reaction.

    Rate = k[A]^x[B]^y, where k is the rate constant and x, y are the orders with respect to A and B.

  2. Define order of a reaction.

    The sum of the powers of the concentration terms in the experimentally determined rate law.

  3. Define molecularity of a reaction.

    The number of reacting species (atoms, ions, or molecules) that collide simultaneously in an elementary reaction; it is always a whole number.

  4. List four factors that affect the rate of a reaction.

    Concentration of reactants, temperature, presence of a catalyst, and surface area (and nature of reactants).

  5. State the Arrhenius equation and what it describes.

    k = A·e^(−Ea/RT), describing the dependence of the rate constant k on temperature; Ea is the activation energy and A is the frequency factor.

  6. Define activation energy.

    The minimum amount of energy that reactant molecules must possess for a reaction to occur (the energy barrier between reactants and products).

  7. How does a catalyst increase reaction rate?

    It provides an alternative reaction pathway with lower activation energy, without being consumed in the reaction.

  8. Why does boiling point of a solvent rise when a non-volatile solute is added?

    The non-volatile solute lowers the solvent's vapour pressure, so a higher temperature is needed to make vapour pressure equal atmospheric pressure — this rise is boiling point elevation.

  9. Give the formula for boiling point elevation.

    ΔTb = Kb × m, where ΔTb is the elevation, Kb is the molal boiling point elevation (ebullioscopic) constant, and m is molality.

  10. Give the formula for freezing point depression.

    ΔTf = Kf × m, where ΔTf is the depression, Kf is the molal freezing point depression (cryoscopic) constant, and m is molality.

  11. What are colligative properties?

    Properties that depend only on the number of solute particles in solution, not their nature: relative lowering of vapour pressure, boiling point elevation, freezing point depression, and osmotic pressure.

  12. What is the van't Hoff factor (i) and why is it used in colligative property calculations?

    i is the ratio of observed to calculated colligative effect; it accounts for dissociation or association of solute particles (e.g., i ≈ 2 for NaCl).

  13. Why is salt spread on icy roads in winter?

    Salt dissolves and depresses the freezing point of water, causing ice to melt at lower temperatures (freezing point depression).

  14. State the First Law of Thermodynamics.

    Energy can neither be created nor destroyed, only converted from one form to another; the internal energy of an isolated system is constant. ΔU = q + w.

  15. In the equation ΔU = q + w, what does each term mean (IUPAC sign convention)?

    ΔU = change in internal energy; q = heat added to the system (positive when absorbed); w = work done on the system (positive when done on it).

  16. Define enthalpy (H) and give its relation to internal energy.

    Enthalpy is the heat content of a system at constant pressure: H = U + PV; the change is ΔH = ΔU + PΔV.

  17. What is the work done in an isothermal reversible expansion of an ideal gas?

    w = −nRT ln(V2/V1) = −2.303 nRT log(V2/V1).

  18. For a reaction at constant volume, how does heat relate to internal energy?

    At constant volume no PV work is done (w = 0), so the heat absorbed equals the change in internal energy: q_v = ΔU.

  19. Define Arrhenius acids and bases.

    An Arrhenius acid produces H⁺ (hydrogen) ions in aqueous solution; an Arrhenius base produces OH⁻ (hydroxide) ions in aqueous solution.

  20. Define Brønsted–Lowry acids and bases.

    A Brønsted–Lowry acid is a proton (H⁺) donor; a Brønsted–Lowry base is a proton acceptor.

  21. Define Lewis acids and bases.

    A Lewis acid is an electron-pair acceptor; a Lewis base is an electron-pair donor.

  22. What is a conjugate acid–base pair?

    Two species that differ by a single proton (H⁺); the acid loses a proton to form its conjugate base, and the base gains a proton to form its conjugate acid (e.g., HCl/Cl⁻).

  23. Define pH and give its formula.

    pH is the negative logarithm of hydrogen ion concentration: pH = −log[H⁺]. Neutral = 7, acidic < 7, basic > 7.

  24. What is the ionic product of water (Kw) at 25°C and the relation between pH and pOH?

    Kw = [H⁺][OH⁻] = 1 × 10⁻¹⁴ at 25°C, and pH + pOH = 14.

What this deck covers

The Physical Chemistry deck follows the GPAT Physical Chemistry syllabus — 8 chapters and 8 topics — so questions land on material that is genuinely examinable rather than trivia around it. That works out to roughly 7.0 cards per chapter.

Answers are written to be recallable, not just readable — averaging about 123 characters, which is long enough to carry the reasoning and short enough to say out loud.

A deck like this earns its keep on the second and third pass. Read the syllabus first so you know the shape of the subject, then use the cards to find the specific facts that have not stuck.

Physical Chemistry flashcards FAQ

How many Physical Chemistry flashcards are in this GPAT deck?

56 cards. This page previews 24 of them, sampled evenly across the deck so you can judge the difficulty before installing anything.

Are these GPAT flashcards free?

Yes. The preview here is free to read with no signup, and the full 56-card deck is free inside the Examius app.

What do the Physical Chemistry cards cover?

They follow the GPAT Physical Chemistry syllabus — 8 chapters and 8 topics — so the questions track what is actually examinable.

How should I use these flashcards?

Read the syllabus first so you know the shape of the subject, then drill the deck. Examius schedules each card with spaced repetition, so cards you keep missing come back sooner and ones you know drift further apart.