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WBJEE Inorganic Chemistry Flashcards

53 question-and-answer cards covering Inorganic Chemistry as it is examined in WBJEE. 24 of them are printed below, taken from across the deck — no signup, no paywall on the preview.

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24 sample cards from the Inorganic Chemistry deck

Sampled from the end of the deck, so these are different cards from the ones shown on the syllabus page.

  1. Name the three isotopes of hydrogen with their mass numbers and composition.

    Protium $\ce{^1_1H}$ (1p, 0n), Deuterium $\ce{^2_1H}$ or D (1p, 1n), and Tritium $\ce{^3_1H}$ or T (1p, 2n). Tritium is radioactive ($\beta$-emitter).

  2. What is water gas (synthesis gas) and how is it produced industrially?

    Water gas is a mixture of $\ce{CO}$ and $\ce{H2}$. It is produced by passing steam over red-hot coke: $$\ce{C(s) + H2O(g) ->[1270\,K] CO(g) + H2(g)}$$

  3. Distinguish temporary and permanent hardness of water, including the responsible salts.

    Temporary hardness is due to dissolved bicarbonates $\ce{Ca(HCO3)2}$ and $\ce{Mg(HCO3)2}$ and is removed by boiling or Clark's method (lime). Permanent hardness is due to chlorides and sulphates ($\ce{CaCl2}$, $\ce{MgSO4}$) and is removed by washing soda or ion-exchange.

  4. What is the structure and key property of hydrogen peroxide ($\ce{H2O2}$) regarding redox behavior?

    $\ce{H2O2}$ has a non-planar open-book structure. It acts as both an oxidizing and a reducing agent in acidic and basic media. Example oxidation: $\ce{2I- + H2O2 + 2H+ -> I2 + 2H2O}$; reduction (toward stronger oxidant): $\ce{2MnO4- + 5H2O2 + 6H+ -> 2Mn^2+ + 5O2 + 8H2O}$.

  5. Classify hydrides into three types with an example of each.

    Ionic/saline hydrides (s-block metals, e.g. $\ce{NaH}$, $\ce{CaH2}$); covalent/molecular hydrides (p-block, e.g. $\ce{CH4}$, $\ce{NH3}$, $\ce{H2O}$); metallic/interstitial hydrides (many d- and f-block metals, often non-stoichiometric, e.g. $\ce{LaH_{2.87}}$).

  6. List the general physical and chemical characteristics of alkali metals (group 1).

    They are soft, low-density, low-melting silvery metals with one valence electron ($ns^{1}$). They are highly electropositive, the most reactive metals, strong reducing agents, form $+1$ ions, and impart characteristic flame colors. Reactivity increases down the group.

  7. Why do alkali metals impart characteristic colors to a flame, and give the colors of $\ce{Li}$, $\ce{Na}$, and $\ce{K}$.

    Flame heat excites valence electrons to higher levels; on returning they emit visible-light photons. $\ce{Li}$ = crimson red, $\ce{Na}$ = golden yellow, $\ce{K}$ = lilac/violet.

  8. What is washing soda, give its formula, and the industrial process for its manufacture.

    Washing soda is sodium carbonate decahydrate, $\ce{Na2CO3.10H2O}$. It is made by the Solvay (ammonia-soda) process, the key step being $\ce{NaCl + NH3 + CO2 + H2O -> NaHCO3 + NH4Cl}$, followed by heating: $\ce{2NaHCO3 ->[\Delta] Na2CO3 + H2O + CO2}$.

  9. Why is $\ce{LiF}$ much less soluble in water than other alkali metal halides like $\ce{LiCl}$?

    $\ce{LiF}$ has a very high lattice enthalpy (both ions are very small), which is not compensated by the hydration enthalpy, so it is sparingly soluble. With larger anions (e.g. $\ce{Cl-}$) lattice enthalpy falls and solubility rises.

  10. State the general properties of alkaline earth metals (group 2) and how they compare to group 1.

    They have $ns^{2}$ configuration, form $+2$ ions, are harder, denser, higher-melting, and less reactive than the corresponding alkali metals. They are good reducing agents but weaker than group 1; reactivity increases down the group.

  11. Compare the solubility trends of group 2 hydroxides and sulphates down the group.

    Solubility of hydroxides increases down the group ($\ce{Mg(OH)2}$ sparingly soluble, $\ce{Ba(OH)2}$ fairly soluble) because hydration enthalpy dominates. Solubility of sulphates decreases down the group ($\ce{BaSO4}$ insoluble) because lattice enthalpy decreases slowly while hydration enthalpy falls sharply for the large cations.

  12. What is dead burnt plaster and Plaster of Paris? Give the formula and setting reaction of Plaster of Paris.

    Plaster of Paris is calcium sulphate hemihydrate, $\ce{CaSO4.\tfrac{1}{2}H2O}$, made by heating gypsum to $\sim 393\,\text{K}$. On adding water it sets to gypsum: $\ce{CaSO4.\tfrac{1}{2}H2O + \tfrac{3}{2}H2O -> CaSO4.2H2O}$. Heating gypsum above $473\,\text{K}$ gives anhydrous 'dead burnt' plaster.

  13. Why is $\ce{BeCl2}$ covalent and a Lewis acid, unlike other group 2 chlorides?

    $\ce{Be^2+}$ is very small with high charge density (high polarizing power, Fajans' rules), so $\ce{BeCl2}$ is essentially covalent. Be has an incomplete octet (electron-deficient), making it a Lewis acid; in the solid/vapour it polymerizes via chloride bridges.

  14. Why does boron show an anomalously high first ionization enthalpy trend break and form only covalent compounds like $\ce{BF3}$ with an incomplete octet?

    Boron is very small with high ionization enthalpy, so it cannot easily lose its 3 valence electrons to form $\ce{B^3+}$; it forms covalent bonds instead. In $\ce{BF3}$ boron has only 6 valence electrons (incomplete octet), making it a strong Lewis acid that accepts a lone pair to complete its octet.

  15. Explain the inert pair effect and its consequence in group 14 (e.g. $\ce{Pb}$).

    The inert pair effect is the reluctance of the $ns^{2}$ electrons to participate in bonding for heavier p-block elements (poor shielding by d/f electrons). In group 14, the $+2$ state becomes more stable than $+4$ down the group, so $\ce{Pb^2+}$ ($\ce{PbCl2}$) is more stable than $\ce{Pb^4+}$.

  16. Why is $\ce{CO2}$ a gas while $\ce{SiO2}$ is a high-melting solid?

    $\ce{CO2}$ is a discrete linear molecule ($\ce{O=C=O}$) with weak intermolecular forces, so it is a gas. $\ce{SiO2}$ forms a giant 3D covalent network of $\ce{Si-O}$ single bonds (Si does not readily form $p\pi$-$p\pi$ bonds), giving a hard, high-melting solid.

  17. Why does carbon form strong multiple bonds and long chains (catenation) far more than silicon?

    Carbon is small and forms strong $\ce{C-C}$ ($\sigma$) and effective $p\pi$-$p\pi$ ($\pi$) bonds. Silicon is larger; its $\ce{Si-Si}$ bonds are weaker and it forms poor $p\pi$-$p\pi$ bonds, so its catenation and multiple-bond tendency are much lower.

  18. Why is the catenation order $\ce{N} \ll \ce{P}$ and why does only nitrogen form $\ce{N2}$ with a triple bond?

    Nitrogen, being small, forms strong $p\pi$-$p\pi$ triple bonds, giving the very stable $\ce{N#N}$ molecule, but its $\ce{N-N}$ single bond is weak (lone-pair repulsion), so it catenates poorly. Phosphorus forms stronger $\ce{P-P}$ single bonds and exists as $\ce{P4}$, with greater catenation than nitrogen.

  19. Describe the industrial manufacture of ammonia (Haber process) with optimum conditions.

    $$\ce{N2(g) + 3H2(g) <=> 2NH3(g)} \quad \Delta H = -92\ \text{kJ mol}^{-1}$$ Optimum conditions: pressure $\sim 200\,\text{atm}$, temperature $\sim 700\,\text{K}$, with finely divided iron catalyst promoted by $\ce{K2O}$ and $\ce{Al2O3}$ (Mo as promoter).

  20. State the trend in thermal stability and reducing character of group 15 hydrides ($\ce{NH3}$ to $\ce{BiH3}$).

    Down the group the $\ce{M-H}$ bond weakens, so thermal stability decreases ($\ce{NH3} > \ce{PH3} > \ce{AsH3} > \ce{SbH3} > \ce{BiH3}$) and reducing character increases ($\ce{BiH3}$ is the strongest reducing agent). Basicity also decreases: $\ce{NH3} > \ce{PH3} > \ce{AsH3} > \ce{SbH3}$.

  21. Describe the manufacture of sulphuric acid by the Contact process, including the key catalytic step.

    Key steps: burn sulphur/pyrites to $\ce{SO2}$; catalytically oxidize $$\ce{2SO2 + O2 <=>[V2O5] 2SO3}$$ (vanadium pentoxide catalyst, $\sim 720\,\text{K}$, $2\,\text{atm}$); absorb $\ce{SO3}$ in conc. $\ce{H2SO4}$ to form oleum $\ce{H2S2O7}$, then dilute: $\ce{H2S2O7 + H2O -> 2H2SO4}$.

  22. Why does fluorine show anomalous behavior such as a low bond dissociation enthalpy of $\ce{F2}$ and only the $-1$ oxidation state?

    $\ce{F2}$ has a low bond enthalpy due to strong repulsion between non-bonding lone pairs on the two small F atoms. Fluorine is the most electronegative element and has no available d-orbitals, so it shows only the $-1$ oxidation state (never positive).

  23. Explain why noble gases are largely inert and which one forms compounds; give an example.

    Noble gases (group 18) have completely filled valence shells ($ns^{2}np^{6}$, He is $1s^{2}$), giving very high ionization enthalpies and near-zero electron gain enthalpy, hence chemical inertness. Xenon, with the lowest ionization enthalpy among the reactive ones, forms fluorides, e.g. $\ce{Xe + F2 ->[673\,K,\,1\,atm] XeF2}$ ($\ce{XeF4}$, $\ce{XeF6}$ under other conditions).

  24. Give the shapes of $\ce{XeF2}$, $\ce{XeF4}$, and $\ce{XeF6}$ from VSEPR.

    $\ce{XeF2}$: linear ($sp^{3}d$, 3 lone pairs). $\ce{XeF4}$: square planar ($sp^{3}d^{2}$, 2 lone pairs). $\ce{XeF6}$: distorted octahedral ($sp^{3}d^{3}$, 1 lone pair).

What this deck covers

The Inorganic Chemistry deck follows the WBJEE Inorganic Chemistry syllabus — 4 chapters and 12 topics — so questions land on material that is genuinely examinable rather than trivia around it. That works out to roughly 13.3 cards per chapter.

Answers are written to be recallable, not just readable — averaging about 258 characters, which is long enough to carry the reasoning and short enough to say out loud.

A deck like this earns its keep on the second and third pass. Read the syllabus first so you know the shape of the subject, then use the cards to find the specific facts that have not stuck.

Inorganic Chemistry flashcards FAQ

How many Inorganic Chemistry flashcards are in this WBJEE deck?

53 cards. This page previews 24 of them, sampled evenly across the deck so you can judge the difficulty before installing anything.

Are these WBJEE flashcards free?

Yes. The preview here is free to read with no signup, and the full 53-card deck is free inside the Examius app.

What do the Inorganic Chemistry cards cover?

They follow the WBJEE Inorganic Chemistry syllabus — 4 chapters and 12 topics — so the questions track what is actually examinable.

How should I use these flashcards?

Read the syllabus first so you know the shape of the subject, then drill the deck. Examius schedules each card with spaced repetition, so cards you keep missing come back sooner and ones you know drift further apart.