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UPSC ESE E&T Communication Systems Flashcards
50 question-and-answer cards covering Communication Systems as it is examined in UPSC ESE E&T. 24 of them are printed below, taken from across the deck — no signup, no paywall on the preview.
24 sample cards from the Communication Systems deck
Sampled from the end of the deck, so these are different cards from the ones shown on the syllabus page.
Give the SNR (in dB) of a uniform PCM system in terms of the number of bits n.
SNR_q ≈ 6.02n + 1.76 dB for a full-load sinusoid. Each additional bit improves the quantization SNR by about 6 dB.
What is companding in PCM and why is it used?
Companding (compressing then expanding) applies nonlinear quantization—finer steps for small signals, coarser for large—to keep SNR roughly constant over the signal range. The A-law (Europe) and μ-law (North America/Japan) are the two standard companding laws.
Compare PCM, DPCM, and Delta Modulation.
PCM encodes each absolute quantized sample (n bits/sample). DPCM encodes the difference between a sample and its prediction, reducing bit rate by exploiting correlation. Delta modulation (DM) is 1-bit DPCM that transmits only the sign of the difference; it is simple but suffers slope overload and granular noise.
What are slope overload distortion and granular noise in delta modulation?
Slope overload occurs when the signal changes faster than the step size can track (step too small). Granular (hunting) noise occurs when the signal is nearly constant and the output oscillates by ±Δ (step too large). Adaptive DM adjusts step size to mitigate both.
Name the three basic binary digital modulation (keying) techniques.
Amplitude-shift keying (ASK), frequency-shift keying (FSK), and phase-shift keying (PSK)—the carrier's amplitude, frequency, or phase respectively is switched according to the binary data.
Why is BPSK more power-efficient (lower BER for a given Eb/N0) than ASK and FSK?
BPSK uses antipodal signals (phases 180° apart), giving the maximum possible distance between the two symbols for a given energy, which minimizes the probability of error. ASK/coherent-FSK use orthogonal/on-off signals with smaller separation, so they need ~3-4 dB more Eb/N0 for the same BER.
What is QPSK and its bandwidth advantage over BPSK?
Quadrature phase-shift keying transmits 2 bits per symbol using four carrier phases (90° apart). For the same bit rate it needs half the bandwidth of BPSK (or doubles data rate in the same bandwidth) while keeping the same BER as BPSK.
How many bits per symbol does M-ary modulation carry, and what is the trade-off?
An M-ary scheme carries log2(M) bits per symbol, improving bandwidth/spectral efficiency. The trade-off is that symbols are packed closer together, so a higher Eb/N0 is required to maintain the same error rate (worse noise immunity).
What is the difference between coherent and non-coherent detection?
Coherent detection requires the receiver to know/recover the exact carrier phase (e.g., PSK, coherent FSK) and gives better BER. Non-coherent detection (e.g., ASK envelope, non-coherent FSK, DPSK) needs no phase reference, is simpler, but performs worse for a given Eb/N0.
What is the purpose of error control coding?
To add controlled redundancy to transmitted data so the receiver can detect and/or correct errors caused by channel noise, thereby improving reliability without retransmission (FEC) or by enabling retransmission requests (ARQ).
Distinguish between FEC and ARQ error control strategies.
Forward Error Correction (FEC) adds redundancy that lets the receiver correct errors without a return channel—good for one-way/real-time links. Automatic Repeat reQuest (ARQ) only detects errors and asks the transmitter to resend the data—needs a feedback channel but is simpler.
Distinguish block codes from convolutional codes.
Block codes (e.g., Hamming, BCH, Reed-Solomon) encode fixed k-bit message blocks into n-bit codewords independently (memoryless). Convolutional codes encode a continuous bit stream using memory (shift registers); each output depends on current and previous input bits, decoded with the Viterbi algorithm.
Define Hamming distance and minimum distance of a code.
Hamming distance between two codewords is the number of bit positions in which they differ. The minimum distance dmin of a code is the smallest Hamming distance between any two distinct codewords; it determines the code's error-detecting and -correcting power.
How do dmin, error detection, and error correction capability relate?
A code with minimum distance dmin can detect up to (dmin − 1) errors and correct up to t = ⌊(dmin − 1)/2⌋ errors. Detection and correction capabilities together require dmin ≥ t + e + 1 for correcting t and detecting e errors.
What is a (7,4) Hamming code and how many errors can it correct?
A linear block code with n = 7 total bits, k = 4 data bits, and 3 parity bits, having minimum distance dmin = 3. It can detect up to 2 errors and correct any single-bit error.
What is data compression and the difference between lossless and lossy compression?
Data compression reduces the number of bits needed to represent information by removing redundancy. Lossless compression (e.g., Huffman, LZW, run-length) allows exact reconstruction; lossy compression (e.g., JPEG, MP3) discards perceptually less important data for higher compression at the cost of fidelity.
What is Huffman coding and its key property?
A lossless, variable-length prefix coding algorithm that assigns shorter codewords to more probable symbols and longer ones to rarer symbols, built from a binary tree merging lowest-probability symbols. It produces an optimal prefix code with minimum average codeword length for known symbol probabilities.
Define the entropy H(X) of a discrete source and its formula.
Entropy is the average information content per symbol: H(X) = −Σ p(xi) log2 p(xi) bits/symbol. It measures the uncertainty of the source and sets the lower bound on the average bits needed to represent it losslessly.
For a source with M equally likely symbols, what is its entropy, and when is entropy maximum?
H = log2(M) bits/symbol when all M symbols are equiprobable. Entropy is maximum precisely when all symbols are equally likely; any nonuniformity reduces entropy below this maximum.
Define information content of a message of probability p and its units.
Self-information I = log2(1/p) = −log2 p, measured in bits (when log base 2). A less probable event carries more information; a certain event (p = 1) carries zero information.
State the Shannon-Hartley channel capacity theorem.
For an AWGN channel, C = B·log2(1 + S/N) bits/second, where B is the bandwidth (Hz) and S/N is the signal-to-noise power ratio. It gives the maximum error-free data rate achievable over the channel.
According to Shannon's channel capacity, what is the trade-off between bandwidth and SNR?
Capacity can be maintained by trading bandwidth against SNR—e.g., wider bandwidth allows the same capacity at lower SNR. However, as B → ∞, capacity approaches a finite limit C_max = 1.44·(S/N0) because noise power also grows with bandwidth (Shannon limit Eb/N0 ≈ −1.6 dB).
State Shannon's source coding theorem and define coding efficiency.
The source coding (noiseless coding) theorem states that the minimum average codeword length per symbol cannot be less than the source entropy H(X), i.e., L̄ ≥ H(X). Coding efficiency η = H(X)/L̄ (often ×100%), and redundancy = 1 − η.
How do parity check, checksum, and CRC compare as error-detection methods?
Single parity adds one bit and detects only odd numbers of errors (weak). Checksum sums data words and detects many errors but can miss reordering/compensating errors. Cyclic Redundancy Check (CRC) uses polynomial division by a generator polynomial, giving strong detection of burst and random errors, and is the most reliable of the three.
What this deck covers
The Communication Systems deck follows the UPSC ESE E&T Communication Systems syllabus — 3 chapters and 12 topics — so questions land on material that is genuinely examinable rather than trivia around it. That works out to roughly 16.7 cards per chapter.
Answers are written to be recallable, not just readable — averaging about 245 characters, which is long enough to carry the reasoning and short enough to say out loud.
A deck like this earns its keep on the second and third pass. Read the syllabus first so you know the shape of the subject, then use the cards to find the specific facts that have not stuck.
Communication Systems flashcards FAQ
How many Communication Systems flashcards are in this UPSC ESE E&T deck?
50 cards. This page previews 24 of them, sampled evenly across the deck so you can judge the difficulty before installing anything.
Are these UPSC ESE E&T flashcards free?
Yes. The preview here is free to read with no signup, and the full 50-card deck is free inside the Examius app.
What do the Communication Systems cards cover?
They follow the UPSC ESE E&T Communication Systems syllabus — 3 chapters and 12 topics — so the questions track what is actually examinable.
How should I use these flashcards?
Read the syllabus first so you know the shape of the subject, then drill the deck. Examius schedules each card with spaced repetition, so cards you keep missing come back sooner and ones you know drift further apart.