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SRMJEEE Chemistry Flashcards

51 question-and-answer cards covering Chemistry as it is examined in SRMJEEE. 24 of them are printed below, taken from across the deck — no signup, no paywall on the preview.

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22Syllabus topics
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24 sample cards from the Chemistry deck

Sampled from the end of the deck, so these are different cards from the ones shown on the syllabus page.

  1. Write the ideal gas equation and identify each term.

    $$PV = nRT$$ where $P$ is pressure, $V$ is volume, $n$ is moles, $T$ is absolute temperature, and $R = 8.314\ \text{J K}^{-1}\text{mol}^{-1} = 0.0821\ \text{L atm K}^{-1}\text{mol}^{-1}$ is the gas constant.

  2. State Dalton's law of partial pressures.

    The total pressure of a mixture of non-reacting gases equals the sum of the partial pressures of the individual gases: $$P_{\text{total}} = P_1 + P_2 + P_3 + \cdots$$

  3. State Avogadro's law.

    Equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules; equivalently, at fixed $T$ and $P$, $V \propto n$.

  4. Write the expression for the root-mean-square speed of gas molecules from kinetic theory.

    $$u_{rms} = \sqrt{\frac{3RT}{M}} = \sqrt{\frac{3kT}{m}}$$ where $M$ is molar mass, $m$ is molecular mass, and $k$ is Boltzmann's constant.

  5. Write the kinetic gas equation and the relation between average kinetic energy and temperature.

    $$PV = \frac{1}{3}mNu^{2}$$ and the average kinetic energy per mole is $E_k = \frac{3}{2}RT$, showing kinetic energy depends only on absolute temperature.

  6. Write the van der Waals equation for real gases and explain the correction terms.

    $$\left(P + \frac{an^{2}}{V^{2}}\right)(V - nb) = nRT$$ The term $\frac{an^{2}}{V^{2}}$ corrects for intermolecular attractive forces and $nb$ corrects for the finite volume of the molecules.

  7. Define compressibility factor $Z$ and state its value for an ideal gas.

    $$Z = \frac{PV}{nRT}$$ For an ideal gas $Z = 1$. $Z < 1$ indicates dominant attractive forces and $Z > 1$ indicates dominant repulsive forces.

  8. Define surface tension and state how it varies with temperature.

    Surface tension is the force per unit length acting along the surface of a liquid (or energy per unit area) that minimizes surface area. It decreases with increasing temperature.

  9. Define viscosity of a liquid and state how it changes with temperature.

    Viscosity is a measure of a liquid's resistance to flow, arising from internal friction between layers. Viscosity decreases with increasing temperature.

  10. What is vapour pressure and when does a liquid boil?

    Vapour pressure is the pressure exerted by the vapour in equilibrium with its liquid at a given temperature. A liquid boils when its vapour pressure equals the external (atmospheric) pressure.

  11. Define ionic and covalent bonding.

    Ionic bonding is the electrostatic attraction between oppositely charged ions formed by transfer of electrons (typically metal to non-metal). Covalent bonding is the sharing of electron pairs between atoms (typically between non-metals).

  12. State the octet rule.

    Atoms tend to gain, lose, or share electrons so as to achieve a stable noble-gas configuration of eight electrons in their valence shell.

  13. Define lattice energy and state Fajans' rules for covalent character in ionic bonds.

    Lattice energy is the energy released when gaseous ions combine to form one mole of an ionic solid. Fajans' rules: covalent character increases with small cation size, large anion size, and high charge on the ions (high polarizing power/polarizability).

  14. What does VSEPR theory predict and what is the basic principle?

    VSEPR (Valence Shell Electron Pair Repulsion) theory predicts molecular geometry based on minimizing repulsion between electron pairs around the central atom. Repulsion order: lone pair–lone pair > lone pair–bond pair > bond pair–bond pair.

  15. Give the hybridisation, shape and bond angle for $\ce{sp}$, $\ce{sp^2}$ and $\ce{sp^3}$ hybridisation.

    $\ce{sp}$: linear, $180^\circ$; $\ce{sp^2}$: trigonal planar, $120^\circ$; $\ce{sp^3}$: tetrahedral, $109.5^\circ$.

  16. State the shape and bond angle of $\ce{H2O}$ and $\ce{NH3}$, and explain the deviation from $109.5^\circ$.

    $\ce{H2O}$ is bent with bond angle $\approx 104.5^\circ$ and $\ce{NH3}$ is trigonal pyramidal with $\approx 107^\circ$. Both are $\ce{sp^3}$ hybridised; lone pair–bond pair repulsion compresses the angle below the ideal $109.5^\circ$.

  17. What is the hybridisation, shape and bond angle of $\ce{PCl5}$ and $\ce{SF6}$?

    $\ce{PCl5}$: $\ce{sp^3d}$ hybridisation, trigonal bipyramidal, bond angles $90^\circ$ and $120^\circ$. $\ce{SF6}$: $\ce{sp^3d^2}$ hybridisation, octahedral, bond angle $90^\circ$.

  18. State the formula for bond order in molecular orbital theory.

    $$\text{Bond order} = \frac{1}{2}\left(N_b - N_a\right)$$ where $N_b$ is the number of electrons in bonding molecular orbitals and $N_a$ in antibonding molecular orbitals.

  19. Use MO theory to explain why $\ce{O2}$ is paramagnetic.

    In $\ce{O2}$ the two highest electrons occupy the degenerate $\pi^{*}_{2p}$ antibonding orbitals singly with parallel spins (Hund's rule), giving two unpaired electrons; these unpaired electrons make $\ce{O2}$ paramagnetic. Its bond order is $2$.

  20. Why does the $\ce{He2}$ molecule not exist according to MO theory?

    $\ce{He2}$ would have configuration $\sigma_{1s}^{2}\sigma_{1s}^{*2}$, giving bond order $= \frac{1}{2}(2-2) = 0$; with zero net bonding the molecule is unstable and does not exist.

  21. State the first law of thermodynamics and its mathematical form.

    Energy can neither be created nor destroyed (conservation of energy). The change in internal energy is $$\Delta U = q + W$$ where $q$ is heat added to the system and $W$ is work done on the system.

  22. Define enthalpy and give the relation between $\Delta H$ and $\Delta U$.

    Enthalpy is $H = U + PV$. For a reaction at constant pressure, $$\Delta H = \Delta U + \Delta(PV) = \Delta U + \Delta n_g RT$$ where $\Delta n_g$ is the change in moles of gas.

  23. State Hess's law of constant heat summation.

    The total enthalpy change of a reaction is the same whether it occurs in one step or several steps, depending only on the initial and final states. Thus enthalpy changes of individual steps can be added to obtain the overall $\Delta H$.

  24. Distinguish between exothermic and endothermic reactions in terms of the sign of $\Delta H$.

    In an exothermic reaction heat is released and $\Delta H < 0$ (negative). In an endothermic reaction heat is absorbed and $\Delta H > 0$ (positive).

What this deck covers

The Chemistry deck follows the SRMJEEE Chemistry syllabus — 5 chapters and 22 topics — so questions land on material that is genuinely examinable rather than trivia around it. That works out to roughly 10.2 cards per chapter.

Answers are written to be recallable, not just readable — averaging about 184 characters, which is long enough to carry the reasoning and short enough to say out loud.

A deck like this earns its keep on the second and third pass. Read the syllabus first so you know the shape of the subject, then use the cards to find the specific facts that have not stuck.

Chemistry flashcards FAQ

How many Chemistry flashcards are in this SRMJEEE deck?

51 cards. This page previews 24 of them, sampled evenly across the deck so you can judge the difficulty before installing anything.

Are these SRMJEEE flashcards free?

Yes. The preview here is free to read with no signup, and the full 51-card deck is free inside the Examius app.

What do the Chemistry cards cover?

They follow the SRMJEEE Chemistry syllabus — 5 chapters and 22 topics — so the questions track what is actually examinable.

How should I use these flashcards?

Read the syllabus first so you know the shape of the subject, then drill the deck. Examius schedules each card with spaced repetition, so cards you keep missing come back sooner and ones you know drift further apart.