🇮🇳 UPSC ESE Electrical Engineering · flashcards
UPSC ESE Electrical Engineering Electrical Engineering Flashcards
55 question-and-answer cards covering Electrical Engineering as it is examined in UPSC ESE Electrical Engineering. 24 of them are printed below, taken from across the deck — no signup, no paywall on the preview.
24 sample cards from the Electrical Engineering deck
Sampled from the end of the deck, so these are different cards from the ones shown on the syllabus page.
State Gauss's law in differential and integral form for electrostatics.
Integral: $\oint \vec{D}\cdot d\vec{A} = Q_{enc}$. Differential: $\nabla\cdot\vec{D} = \rho$, where $\vec{D} = \varepsilon\vec{E}$.
Write the electric field and potential due to a point charge $Q$ at distance $r$ in free space.
$\vec{E} = \frac{Q}{4\pi\varepsilon_{0}r^{2}}\hat{r}$ and $V = \frac{Q}{4\pi\varepsilon_{0}r}$.
State Ampere's circuital law (magnetostatics) in integral form.
$\oint \vec{H}\cdot d\vec{l} = I_{enc}$. In differential form $\nabla\times\vec{H} = \vec{J}$ (for steady currents).
Write the energy stored per unit volume in electric and magnetic fields.
Electric: $w_{e} = \frac{1}{2}\varepsilon E^{2}$. Magnetic: $w_{m} = \frac{1}{2}\mu H^{2}$ (or $\frac{B^{2}}{2\mu}$).
State the EMF equation of a transformer.
$E = 4.44\,f\,N\,\Phi_{m}$, where $f$ is frequency, $N$ the number of turns, and $\Phi_{m}$ the maximum core flux.
Write the transformer voltage, current and impedance transformation ratios.
$\frac{V_{1}}{V_{2}} = \frac{N_{1}}{N_{2}} = a$, $\frac{I_{1}}{I_{2}} = \frac{N_{2}}{N_{1}} = \frac{1}{a}$, and referred impedance $Z' = a^{2}Z$.
Name the two main loss types in a transformer and how each varies with load.
Core (iron) losses: hysteresis + eddy current, essentially constant (independent of load). Copper losses: $I^{2}R$, vary with the square of load current.
What is the condition for maximum efficiency in a transformer?
Maximum efficiency occurs when copper losses equal iron losses: $I^{2}R = P_{iron}$. The corresponding load fraction is $\sqrt{\frac{P_{iron}}{P_{cu,fl}}}$.
Define voltage regulation of a transformer.
$\%\text{Reg} = \frac{V_{no\text{-}load} - V_{full\text{-}load}}{V_{full\text{-}load}}\times 100$. Lower regulation indicates a stiffer (better) transformer.
Write the EMF equation of a DC machine.
$E_{b} = \frac{P\Phi Z N}{60 A}$, where $P$=poles, $\Phi$=flux/pole, $Z$=conductors, $N$=speed (rpm), $A$=parallel paths (lap $A=P$, wave $A=2$).
Write the torque equation of a DC motor.
$T = \frac{P\Phi Z I_{a}}{2\pi A}$, i.e. $T \propto \Phi I_{a}$. Electromagnetic torque $T = \frac{E_{b}I_{a}}{2\pi N/60}$.
Give the back-EMF/voltage relation in a DC motor and the speed equation.
$V = E_{b} + I_{a}R_{a}$, so $N \propto \frac{E_{b}}{\Phi} = \frac{V - I_{a}R_{a}}{\Phi}$.
Compare speed-torque behaviour of DC series and shunt motors.
Series: high starting torque ($T \propto I_{a}^{2}$), speed varies widely (runs away on no load). Shunt: nearly constant speed, moderate starting torque ($T \propto I_{a}$).
Define slip $s$ of an induction motor.
$s = \frac{N_{s} - N_{r}}{N_{s}}$, where synchronous speed $N_{s} = \frac{120 f}{P}$ and $N_{r}$ is rotor speed.
Write the relationship between rotor copper loss, air-gap power and slip in an induction motor.
Rotor copper loss $= s \times P_{ag}$ (air-gap power); mechanical power developed $= (1-s)P_{ag}$. Thus $P_{ag} : P_{cu,rotor} : P_{mech} = 1 : s : (1-s)$.
What is the rotor frequency of an induction motor in terms of slip?
$f_{r} = s f$, where $f$ is the stator supply frequency. At standstill ($s=1$) rotor frequency equals supply frequency.
State the condition for maximum torque in an induction motor in terms of rotor parameters.
Maximum torque occurs when rotor resistance equals rotor reactance per phase: $\frac{R_{2}}{s} = X_{2}$, i.e. slip at max torque $s_{m} = \frac{R_{2}}{X_{2}}$. Max torque is independent of $R_{2}$.
Write the synchronous speed formula and EMF equation of a synchronous machine.
$N_{s} = \frac{120 f}{P}$. EMF: $E = 4.44\,f\,\Phi\,T\,k_{w}$, where $k_{w}$ is the winding factor and $T$ turns per phase.
Write the power-angle equation of a cylindrical-rotor synchronous machine.
$P = \frac{E V}{X_{s}}\sin\delta$, where $\delta$ is the load (torque) angle. Maximum (pull-out) power occurs at $\delta = 90^{\circ}$.
How does field excitation affect a synchronous motor's power factor (V-curves)?
Under-excitation draws lagging current; over-excitation draws leading current (acts as a synchronous condenser); normal excitation gives unity PF. V-curves plot armature current vs field current.
Why is a single-phase induction motor not self-starting, and how is it made self-starting?
Its pulsating field gives zero net starting torque (two equal counter-rotating fields). Starting is provided by an auxiliary winding for phase splitting: split-phase, capacitor-start, or shaded-pole methods.
What is a permanent magnet (PM) machine and one key advantage over wound-field machines?
A machine where field excitation is provided by permanent magnets instead of a field winding. Advantages: no field copper loss/excitation supply, higher efficiency and power density. Examples: BLDC and PMSM motors.
Describe the basic operating principle of a stepper motor and its step angle formula.
A stepper rotates in discrete steps, one per input pulse, with position proportional to pulse count. Step angle $= \frac{360^{\circ}}{m \times N_{r}}$ (phases $\times$ rotor teeth), e.g. variable-reluctance, PM, and hybrid types.
State the relationship between mechanical power, torque and speed used in power/machine analysis.
$P = T\omega = T\times\frac{2\pi N}{60}$, where $T$ is in N·m, $N$ in rpm, and $\omega$ in rad/s.
What this deck covers
The Electrical Engineering deck follows the UPSC ESE Electrical Engineering Electrical Engineering syllabus — 8 chapters and 57 topics — so questions land on material that is genuinely examinable rather than trivia around it. That works out to roughly 6.9 cards per chapter.
Answers are written to be recallable, not just readable — averaging about 146 characters, which is long enough to carry the reasoning and short enough to say out loud.
A deck like this earns its keep on the second and third pass. Read the syllabus first so you know the shape of the subject, then use the cards to find the specific facts that have not stuck.
Electrical Engineering flashcards FAQ
How many Electrical Engineering flashcards are in this UPSC ESE Electrical Engineering deck?
55 cards. This page previews 24 of them, sampled evenly across the deck so you can judge the difficulty before installing anything.
Are these UPSC ESE Electrical Engineering flashcards free?
Yes. The preview here is free to read with no signup, and the full 55-card deck is free inside the Examius app.
What do the Electrical Engineering cards cover?
They follow the UPSC ESE Electrical Engineering Electrical Engineering syllabus — 8 chapters and 57 topics — so the questions track what is actually examinable.
How should I use these flashcards?
Read the syllabus first so you know the shape of the subject, then drill the deck. Examius schedules each card with spaced repetition, so cards you keep missing come back sooner and ones you know drift further apart.