🇮🇳 UPSC ESE Mechanical Engineering · subject
UPSC ESE Mechanical Engineering Engineering Mechanics Syllabus
The Engineering Mechanics syllabus for UPSC ESE Mechanical Engineering in full: 3 chapters and 9 topics, every one listed below, plus 50 Engineering Mechanics flashcards with answers.
Engineering Mechanics syllabus: all 3 chapters
Expand any chapter to see its topics and sub-topics.
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Statics
3 topics- Equilibrium of Forces
- Trusses and Frames
- Friction
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Dynamics
3 topics- Kinematics
- Kinetics
- Work and Energy
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Vibrations
3 topics- Free and Forced Vibrations
- Damping
- Resonance
UPSC ESE Mechanical Engineering Engineering Mechanics flashcards — 50 questions with answers
State the necessary and sufficient conditions for the equilibrium of a coplanar (2D) system of forces.
The vector sum of all forces and the sum of moments about any point must vanish: $\sum F_x = 0$, $\sum F_y = 0$, and $\sum M_z = 0$.
How many independent equilibrium equations are available for a general three-dimensional rigid body?
Six: $\sum F_x = 0$, $\sum F_y = 0$, $\sum F_z = 0$ and $\sum M_x = 0$, $\sum M_y = 0$, $\sum M_z = 0$.
State Lami's theorem for three concurrent coplanar forces in equilibrium.
If three forces keep a particle in equilibrium, each force is proportional to the sine of the angle between the other two: $\dfrac{P}{\sin\alpha} = \dfrac{Q}{\sin\beta} = \dfrac{R}{\sin\gamma}$.
What is the moment of a force about a point, expressed as a vector?
$\vec{M} = \vec{r} \times \vec{F}$, where $\vec{r}$ is the position vector from the point to any point on the line of action of $\vec{F}$. Its magnitude is $M = F d$, with $d$ the perpendicular distance.
Define a couple and give the magnitude of its moment.
A couple is a pair of equal, opposite, non-collinear parallel forces. Its moment $M = F \times d$ (force times perpendicular separation) is a free vector, the same about every point.
State Varignon's theorem (principle of moments).
The moment of a resultant force about any point equals the algebraic sum of the moments of its component forces about the same point: $\vec{r}\times\vec{R} = \sum \vec{r}\times\vec{F_i}$.
What is a free-body diagram and why is it essential in statics?
A free-body diagram isolates a body and shows all external forces and reactions acting on it, with the body removed from its supports. It is essential for correctly applying the equilibrium equations.
Define a two-force member and state a key property.
A member loaded by forces at only two points (and no moments). For equilibrium the two forces must be equal, opposite, and collinear along the line joining the two points (purely axial).
What is a perfect (statically determinate) plane truss? Give the relation between members $m$ and joints $j$.
A truss with just enough members to be rigid and solvable by statics alone: $m = 2j - 3$. If $m > 2j-3$ it is redundant (indeterminate); if $m < 2j-3$ it is deficient (a mechanism).
List the standard assumptions made in the analysis of an ideal pin-jointed truss.
Members are straight and connected by frictionless pins; loads and reactions act only at joints; member weight is neglected (or split to joints); each member carries only axial force (tension or compression).
Describe the method of joints for truss analysis.
Isolate each joint as a particle in equilibrium and apply $\sum F_x = 0$ and $\sum F_y = 0$ (two equations per joint). Start at a joint with at most two unknown member forces and proceed sequentially.
Describe the method of sections for truss analysis and its advantage.
Cut the truss through the members of interest (ideally three) and apply $\sum F_x=0$, $\sum F_y=0$, $\sum M=0$ to one part. Advantage: it directly gives the force in a specific interior member without solving every joint.
What is a zero-force member, and give two rules for identifying one by inspection?
A member carrying no axial force. (1) At an unloaded joint with only two non-collinear members, both are zero-force. (2) At an unloaded joint with three members where two are collinear, the third (non-collinear) member is zero-force.
How do you determine static determinacy of a plane frame (rigid jointed) with $m$ members, $r$ reactions, and $j$ joints?
Degree of static indeterminacy $D_s = 3m + r - 3j$. If $D_s = 0$ it is determinate, $D_s > 0$ indeterminate, $D_s < 0$ unstable.
State the laws of static (Coulomb) dry friction.
Friction opposes impending/relative motion; $F \le \mu_s N$ with limiting value $F_{max} = \mu_s N$; it is independent of the apparent contact area; and it depends on the nature of the surfaces in contact.
Define the coefficient of static friction and write the limiting friction relation.
$\mu_s = \dfrac{F_{max}}{N}$, the ratio of the limiting friction force at impending motion to the normal reaction. At impending motion $F_{max} = \mu_s N$.
Define the angle of friction $\phi$ and relate it to $\mu$.
The angle between the resultant reaction and the normal at impending motion: $\tan\phi = \mu$. The resultant lies on a cone of semi-angle $\phi$ (the cone of friction).
Define the angle of repose and state its relation to the angle of friction.
The maximum inclination of a plane at which a body just begins to slide under its own weight. The angle of repose equals the angle of friction: $\theta_{repose} = \phi$, so $\tan\theta = \mu_s$.
For a body on an incline of angle $\theta$ on the verge of sliding down, what is the friction force in terms of weight $W$?
$F = W\sin\theta$ and $N = W\cos\theta$; at impending motion $\mu_s = \tan\theta$. The minimum force along the plane to prevent sliding is $W(\sin\theta - \mu_s\cos\theta)$.
State the belt friction (capstan) equation for a flat belt about to slip.
$\dfrac{T_1}{T_2} = e^{\mu\beta}$, where $T_1$ is the tight-side tension, $T_2$ the slack-side tension, $\mu$ the coefficient of friction, and $\beta$ the angle of wrap in radians.
Show the other 30 Engineering Mechanics flashcards
Distinguish between kinematics and kinetics.
Kinematics studies motion (position, velocity, acceleration) without reference to its causes. Kinetics relates the motion to the forces and moments that produce it.
Write the three equations of motion for constant (uniform) acceleration.
$v = u + at$, $\;s = ut + \tfrac{1}{2}at^{2}$, and $\;v^{2} = u^{2} + 2as$.
For motion in a plane, define velocity and acceleration as derivatives of position.
$\vec{v} = \dfrac{d\vec{r}}{dt}$ and $\vec{a} = \dfrac{d\vec{v}}{dt} = \dfrac{d^{2}\vec{r}}{dt^{2}}$.
Give the normal and tangential components of acceleration for curvilinear motion.
Tangential: $a_t = \dfrac{dv}{dt}$ (changes speed). Normal (centripetal): $a_n = \dfrac{v^{2}}{\rho}$ toward the center of curvature, where $\rho$ is the radius of curvature. Total $a = \sqrt{a_t^{2}+a_n^{2}}$.
For projectile motion launched at speed $u$ and angle $\theta$ (no air resistance), give time of flight, max height, and range.
Time of flight $T = \dfrac{2u\sin\theta}{g}$; maximum height $H = \dfrac{u^{2}\sin^{2}\theta}{2g}$; horizontal range $R = \dfrac{u^{2}\sin 2\theta}{g}$ (max at $\theta = 45^\circ$).
Write the kinematic equations for rotation with constant angular acceleration $\alpha$.
$\omega = \omega_0 + \alpha t$, $\;\theta = \omega_0 t + \tfrac{1}{2}\alpha t^{2}$, and $\;\omega^{2} = \omega_0^{2} + 2\alpha\theta$.
Relate linear velocity and tangential acceleration of a point to the angular motion of a rotating rigid body.
$v = \omega r$ and tangential acceleration $a_t = \alpha r$, where $r$ is the distance from the axis of rotation; the normal acceleration is $a_n = \omega^{2} r$.
State Newton's second law for a particle and for rotation of a rigid body.
Translation: $\vec{F} = m\vec{a}$. Rotation about a fixed axis: $M = I\alpha$, where $I$ is the mass moment of inertia and $\alpha$ the angular acceleration.
Define the instantaneous center of rotation (ICR) for a rigid body in plane motion.
The point in the body (or its extension) that has zero velocity at a given instant; the body appears to rotate purely about it, so any point's velocity is $v = \omega \times (\text{distance to ICR})$, directed perpendicular to the line to the ICR.
State D'Alembert's principle.
A moving body can be treated as in equilibrium by introducing a fictitious inertia force $-m\vec{a}$ (and inertia couple $-I\alpha$): $\vec{F} - m\vec{a} = 0$, converting a dynamics problem into a statics-type problem.
State the impulse-momentum principle for a particle.
The impulse of the net force equals the change in linear momentum: $\displaystyle\int_{t_1}^{t_2}\vec{F}\,dt = m\vec{v_2} - m\vec{v_1}$.
State the principle of conservation of linear momentum.
If the net external force on a system is zero, total linear momentum is conserved: $m_1\vec{u_1} + m_2\vec{u_2} = m_1\vec{v_1} + m_2\vec{v_2}$.
Define the coefficient of restitution $e$ for a direct central impact.
$e = \dfrac{\text{relative velocity of separation}}{\text{relative velocity of approach}} = \dfrac{v_2 - v_1}{u_1 - u_2}$. $e=1$ for perfectly elastic, $e=0$ for perfectly plastic impact ($0 \le e \le 1$).
Define work done by a constant force and by a variable force.
Constant force: $W = \vec{F}\cdot\vec{d} = Fd\cos\theta$. Variable force along a path: $W = \displaystyle\int \vec{F}\cdot d\vec{s}$.
Write the expressions for translational and rotational kinetic energy.
Translational: $KE = \tfrac{1}{2}mv^{2}$. Rotational: $KE = \tfrac{1}{2}I\omega^{2}$. For general plane motion: $KE = \tfrac{1}{2}mv_G^{2} + \tfrac{1}{2}I_G\omega^{2}$.
State the work-energy principle (theorem) for a particle.
The net work done by all forces on a particle equals the change in its kinetic energy: $W_{net} = \Delta KE = \tfrac{1}{2}mv^{2} - \tfrac{1}{2}mu^{2}$.
Give the expression for gravitational potential energy and elastic (spring) potential energy.
Gravitational: $PE = mgh$. Elastic spring: $PE = \tfrac{1}{2}kx^{2}$, where $k$ is the stiffness and $x$ the deformation from the natural length.
State the principle of conservation of mechanical energy and the condition for its validity.
When only conservative forces act, total mechanical energy is constant: $KE + PE = \text{constant}$, i.e. $\tfrac{1}{2}mv_1^{2} + mgh_1 = \tfrac{1}{2}mv_2^{2} + mgh_2$. It holds only when non-conservative forces (e.g. friction) do no work.
Define power and give its expression in terms of force and velocity.
Power is the rate of doing work: $P = \dfrac{dW}{dt} = \vec{F}\cdot\vec{v} = Fv\cos\theta$. For rotation, $P = T\omega$ (torque times angular velocity).
Define simple harmonic motion (SHM) and write its governing differential equation.
Motion where acceleration is proportional to displacement and directed toward the mean position: $\ddot{x} + \omega_n^{2}x = 0$, with solution $x = A\sin(\omega_n t + \phi)$.
For a spring-mass system, give the natural frequency of free undamped vibration.
$\omega_n = \sqrt{\dfrac{k}{m}}$ (rad/s); natural frequency $f_n = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$ (Hz); time period $T = 2\pi\sqrt{\dfrac{m}{k}}$.
Distinguish between free and forced vibrations.
Free vibration occurs at the natural frequency after an initial disturbance with no continuing external force. Forced vibration is sustained by a continuous external periodic excitation, and the body vibrates at the forcing frequency.
Write the equation of motion for a damped free single-degree-of-freedom system.
$m\ddot{x} + c\dot{x} + kx = 0$, where $m$ is mass, $c$ the viscous damping coefficient, and $k$ the stiffness.
Define the damping factor (damping ratio) $\zeta$ and the critical damping coefficient $c_c$.
Critical damping $c_c = 2\sqrt{km} = 2m\omega_n$. Damping ratio $\zeta = \dfrac{c}{c_c} = \dfrac{c}{2\sqrt{km}}$.
Classify the damping of a free vibration system by the value of $\zeta$.
$\zeta = 0$: undamped; $0 < \zeta < 1$: underdamped (oscillatory decay); $\zeta = 1$: critically damped (fastest non-oscillatory return); $\zeta > 1$: overdamped (sluggish, non-oscillatory).
Give the damped natural frequency for an underdamped system.
$\omega_d = \omega_n\sqrt{1 - \zeta^{2}}$, which is always less than the undamped natural frequency $\omega_n$.
Define the logarithmic decrement $\delta$ and relate it to the damping ratio.
$\delta = \ln\dfrac{x_n}{x_{n+1}}$, the natural log of the ratio of successive amplitudes. It relates to damping by $\delta = \dfrac{2\pi\zeta}{\sqrt{1-\zeta^{2}}}$.
Define resonance and state the condition at which it occurs.
Resonance is the condition where the forcing frequency equals the system's natural frequency ($\omega = \omega_n$), producing maximum amplitude (theoretically infinite for an undamped system). Damping limits the peak amplitude.
Define the magnification factor (dynamic amplification factor) for forced vibration.
$M.F. = \dfrac{1}{\sqrt{(1 - r^{2})^{2} + (2\zeta r)^{2}}}$, the ratio of dynamic to static deflection, where $r = \dfrac{\omega}{\omega_n}$ is the frequency ratio.
Define transmissibility in forced vibration and give the frequency ratio beyond which isolation occurs.
Transmissibility is the ratio of force transmitted to the foundation to the applied force: $T_r = \dfrac{\sqrt{1+(2\zeta r)^{2}}}{\sqrt{(1-r^{2})^{2}+(2\zeta r)^{2}}}$. Isolation ($T_r < 1$) occurs only when $r > \sqrt{2}$.
UPSC ESE Mechanical Engineering Engineering Mechanics FAQ
What is in the UPSC ESE Mechanical Engineering Engineering Mechanics syllabus?
UPSC ESE Mechanical Engineering Engineering Mechanics is split into 3 chapters: Statics, Dynamics and Vibrations. Together they contain 9 topics.
How many chapters are in UPSC ESE Mechanical Engineering Engineering Mechanics?
3 chapters, containing 9 topics. The largest chapter is Statics, with 3 topics.
Are there flashcards for UPSC ESE Mechanical Engineering Engineering Mechanics?
Yes — a 50-card Engineering Mechanics deck, printed in full in the flashcards section of this page and available in the Examius app with spaced repetition. The free plan covers one exam of your choice, including its flashcards; Examius Pro, a one-time purchase, unlocks every other exam and deck.