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MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences Syllabus

The Organic Chemistry for the Biological Sciences syllabus for MCAT (Medical College Admission Test) in full: 3 chapters, 10 topics and 24 sub-topics, every one listed below, plus 50 Organic Chemistry for the Biological Sciences flashcards with answers.

3Chapters
10Topics
24Sub-topics
50Flashcards

Organic Chemistry for the Biological Sciences syllabus: all 3 chapters

Expand any chapter to see its topics and sub-topics.

  1. Structure, Bonding, and Stereochemistry

    3 topics
    • Molecular Structure and Nomenclature
      • IUPAC naming of functional groups
      • Hybridization and resonance
    • Isomerism
      • Constitutional isomers and conformations
      • Enantiomers, diastereomers, and chirality
      • R/S and E/Z designation, optical activity
    • Acid-Base Chemistry in Organic Systems
      • Predicting acidity and basicity from structure
      • Resonance and inductive effects
  2. Reaction Mechanisms and Functional Group Chemistry

    4 topics
    • Substitution and Elimination
      • SN1, SN2, E1, and E2 mechanisms
      • Nucleophiles, electrophiles, and leaving groups
    • Carbonyl Chemistry
      • Aldehydes and ketones: nucleophilic addition
      • Carboxylic acids and derivatives
      • Keto-enol tautomerism and aldol reactions
    • Alcohols, Amines, and Ethers
      • Oxidation and reduction of alcohols
      • Amine reactivity and synthesis
    • Biologically Relevant Reactions
      • Esterification and amide bond formation
      • Phosphorylation and redox in biomolecules
  3. Separation, Purification, and Spectroscopy

    3 topics
    • Separation and Purification Techniques
      • Extraction and distillation
      • Chromatography (TLC, column, gas, HPLC)
      • Recrystallization and electrophoresis
    • Spectroscopy
      • Infrared (IR) spectroscopy
      • Nuclear magnetic resonance (NMR) spectroscopy
      • UV-Vis and mass spectrometry
    • Structure Determination and Lab Analysis
      • Interpreting combined spectra to assign structure
      • Measuring purity, melting point, and optical rotation

MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences flashcards — 50 questions with answers

  1. In IUPAC nomenclature, how do you determine the parent chain and the direction of numbering for a substituted alkane?

    Choose the longest continuous carbon chain containing the highest-priority functional group as the parent, then number from the end that gives the principal characteristic group (or, if none, the substituents) the lowest set of locants.

  2. What hybridization and bond angle are associated with sp, sp2, and sp3 carbon atoms?

    sp = linear, 180 degrees (2 sigma + 2 pi possible); sp2 = trigonal planar, 120 degrees (3 sigma + 1 pi); sp3 = tetrahedral, 109.5 degrees (4 sigma).

  3. What is the IUPAC priority order of common functional groups for naming (highest to lowest suffix priority)?

    Carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine > alkene/alkyne. Higher-priority groups get the lowest locant and the suffix; lower ones become prefixes.

  4. What is the difference between a constitutional (structural) isomer and a stereoisomer?

    Constitutional isomers have the same molecular formula but different connectivity of atoms; stereoisomers have the same connectivity but differ in the spatial arrangement of atoms.

  5. Define enantiomers, diastereomers, and meso compounds.

    Enantiomers are non-superimposable mirror images (all stereocenters inverted). Diastereomers are stereoisomers that are not mirror images (some but not all stereocenters differ). A meso compound has stereocenters but is achiral due to an internal plane of symmetry.

  6. How is absolute configuration (R/S) assigned to a stereocenter?

    Rank the four substituents by CIP priority (higher atomic number first). Orient the lowest priority group away from you; if the remaining 1->2->3 sequence is clockwise it is R, counterclockwise it is S. Reverse the call if the lowest priority points toward you.

  7. For a molecule with n stereocenters, what is the maximum number of stereoisomers, and why might there be fewer?

    Maximum is 2^n stereoisomers. There are fewer when internal symmetry creates meso compounds, which reduces the count.

  8. What is the relationship between specific rotation and a racemic mixture?

    Specific rotation measures how much a chiral compound rotates plane-polarized light. A racemic mixture is a 50:50 mix of enantiomers; their rotations cancel, giving a net optical rotation of zero (optically inactive).

  9. What factors stabilize a conjugate base and thereby increase the acidity of an organic acid?

    Acidity increases when the conjugate base is more stable: greater electronegativity of the atom bearing the charge, larger atomic size (better charge dispersal), resonance delocalization, inductive electron withdrawal by nearby groups, and s-character of the orbital holding the lone pair.

  10. Rank the relative acidity of a carboxylic acid, alcohol, water, and terminal alkyne, and give the trend in pKa.

    Carboxylic acid (pKa ~4-5) > water (pKa ~15.7) > alcohol (pKa ~16-18) > terminal alkyne (pKa ~25). Lower pKa means stronger acid; carboxylic acids are most acidic due to resonance-stabilized carboxylate.

  11. How does an electron-withdrawing substituent (e.g., -Cl, -NO2) affect the acidity of a nearby carboxylic acid?

    It increases acidity (lowers pKa) by stabilizing the carboxylate conjugate base through the inductive effect; the effect weakens with distance from the carboxyl group.

  12. Distinguish a Bronsted-Lowry acid/base from a Lewis acid/base.

    A Bronsted-Lowry acid donates a proton (H+) and a base accepts it. A Lewis acid accepts an electron pair and a Lewis base donates an electron pair; the Lewis definition is broader and includes reactions with no proton transfer.

  13. Compare the SN1 and SN2 mechanisms with respect to kinetics, stereochemistry, and substrate preference.

    SN2 is bimolecular (rate depends on substrate and nucleophile), one step, gives inversion (Walden inversion), and favors primary/methyl substrates. SN1 is unimolecular (rate depends only on substrate), two steps via a carbocation, gives racemization, and favors tertiary substrates.

  14. Compare the E1 and E2 elimination mechanisms.

    E2 is concerted/bimolecular, requires a strong base, and needs anti-periplanar geometry between the leaving group and beta-H. E1 is two-step/unimolecular via a carbocation, favored by weak bases and good ionizing solvents, and forms the more substituted (Zaitsev) alkene.

  15. What is the difference between the Zaitsev and Hofmann products in elimination reactions, and what favors each?

    The Zaitsev product is the more substituted, more stable alkene (favored by small bases). The Hofmann product is the less substituted alkene (favored by bulky, sterically hindered bases such as tert-butoxide).

  16. What factors make a good leaving group, and rank halides as leaving groups?

    Good leaving groups are weak bases that stabilize negative charge (stable as anions). Halide leaving-group ability: I- > Br- > Cl- >> F-.

  17. How does solvent type (protic vs aprotic) influence SN1 vs SN2 reactions?

    Polar protic solvents stabilize carbocations and favor SN1/E1 (they also solvate and weaken nucleophiles). Polar aprotic solvents (e.g., DMSO, DMF, acetone) do not solvate nucleophiles strongly, increasing nucleophile reactivity and favoring SN2.

  18. What is the general mechanism of nucleophilic addition to a carbonyl (aldehyde/ketone)?

    A nucleophile attacks the electrophilic carbonyl carbon, breaking the C=O pi bond and pushing electrons onto oxygen to form a tetrahedral alkoxide intermediate, which is then protonated to give the addition product.

  19. Why are aldehydes generally more reactive than ketones toward nucleophilic addition?

    Aldehydes are more reactive because they have less steric hindrance (only one alkyl/H group) and less electron donation to the carbonyl carbon, leaving it more electrophilic than in ketones, which have two electron-donating alkyl groups.

  20. What are the products of reacting an aldehyde/ketone with one and with two equivalents of alcohol under acid catalysis?

    One equivalent of alcohol gives a hemiacetal (or hemiketal); two equivalents (with loss of water) give an acetal (or ketal). Acetals are commonly used as protecting groups for carbonyls.

Show the other 30 Organic Chemistry for the Biological Sciences flashcards
  1. What is keto-enol tautomerism and which form usually predominates?

    Keto-enol tautomerism is the equilibrium between a keto form (C=O with alpha C-H) and an enol form (C=C-OH) via proton transfer. The keto form usually predominates because the C=O bond is stronger/more stable.

  2. What is the aldol condensation, and what product results?

    In an aldol reaction, the enolate of one carbonyl attacks the carbonyl carbon of another, forming a beta-hydroxy aldehyde/ketone (aldol). Under heat/base, dehydration gives an alpha,beta-unsaturated carbonyl (the condensation product).

  3. Rank the relative reactivity of carboxylic acid derivatives toward nucleophilic acyl substitution.

    Acid chloride > acid anhydride > ester ~ carboxylic acid > amide. Reactivity decreases as the leaving group becomes a worse leaving group and as the heteroatom donates more electron density into the carbonyl.

  4. How are alcohols classified, and how does class affect oxidation products?

    Alcohols are primary, secondary, or tertiary based on the number of carbons attached to the carbinol carbon. Primary alcohols oxidize to aldehydes then carboxylic acids; secondary oxidize to ketones; tertiary alcohols generally do not oxidize (no alpha-H on the C-OH).

  5. What reagent selectively oxidizes a primary alcohol to an aldehyde (stopping before the carboxylic acid), and what reagent oxidizes fully to the acid?

    PCC (pyridinium chlorochromate) in anhydrous conditions stops at the aldehyde. Strong aqueous oxidants like Jones reagent (CrO3/H2SO4) or KMnO4 oxidize a primary alcohol all the way to the carboxylic acid.

  6. How do you convert an alcohol into a good leaving group for substitution/elimination?

    Protonate it under acidic conditions (to make water the leaving group) or convert -OH into a tosylate (TsCl) or a halide (e.g., SOCl2, PBr3), turning the poor -OH leaving group into a much better one.

  7. Compare the basicity of aliphatic amines, ammonia, and amides.

    Aliphatic amines are more basic than ammonia (alkyl groups donate electron density). Amides are very weakly basic because the nitrogen lone pair is delocalized into the carbonyl by resonance, reducing its availability.

  8. What is the Williamson ether synthesis?

    It is an SN2 reaction in which an alkoxide (RO-) attacks a primary alkyl halide to form an ether (R-O-R'). Best yields use a primary, unhindered alkyl halide to avoid competing elimination.

  9. Why do alcohols have higher boiling points than ethers or amines of similar molecular weight?

    Alcohols form strong intermolecular hydrogen bonds via O-H. Ethers cannot hydrogen-bond as donors (no O-H), and N-H hydrogen bonds in amines are weaker than O-H, so alcohols boil highest.

  10. In carbohydrate chemistry, what is mutarotation?

    Mutarotation is the change in optical rotation as alpha- and beta-anomers of a sugar interconvert through the open-chain form in solution until reaching an equilibrium mixture of anomers.

  11. What type of bond links amino acids in proteins, and how is it formed?

    A peptide (amide) bond links amino acids, formed by a condensation (dehydration) reaction between the carboxyl group of one amino acid and the amino group of the next, releasing water.

  12. What is the difference between an alpha and beta glycosidic linkage in carbohydrates?

    In an alpha linkage the glycosidic oxygen at the anomeric carbon points down (opposite the CH2OH reference, axial in glucose); in a beta linkage it points up (same side, equatorial). Example: starch is alpha-1,4; cellulose is beta-1,4.

  13. What functional-group transformation occurs in the formation of a triglyceride from glycerol and fatty acids?

    Three fatty acid carboxyl groups undergo esterification with the three hydroxyl groups of glycerol, forming three ester bonds and releasing three water molecules.

  14. What is the role of a coenzyme like NAD+/NADH in biologically relevant redox reactions?

    NAD+ acts as an oxidizing agent, accepting a hydride (2 electrons + 1 proton) to become NADH; NADH is the reducing agent that donates the hydride back. They shuttle reducing equivalents in metabolic redox reactions.

  15. What principle underlies separation by extraction (liquid-liquid extraction)?

    Extraction separates compounds based on differential solubility (partitioning) between two immiscible solvents (usually aqueous and organic). Adjusting pH can ionize acids or bases to pull them into the aqueous layer (acid-base extraction).

  16. How does distillation separate a mixture, and when is fractional distillation needed?

    Distillation separates liquids by differences in boiling point: the more volatile component vaporizes and is condensed first. Fractional distillation is needed when boiling points are close (typically within ~25 degrees C), using a column for repeated vaporization-condensation cycles.

  17. What is the principle of thin-layer chromatography (TLC) and the Rf value?

    TLC separates compounds by their relative affinity for a polar stationary phase (silica) versus a mobile solvent. Rf = (distance traveled by spot)/(distance traveled by solvent front); more polar compounds have lower Rf on silica.

  18. How does column chromatography separate compounds and in what order do they elute on normal-phase silica?

    Compounds separate by polarity differences in affinity for the stationary phase. On normal-phase (polar) silica, less polar compounds elute first and more polar compounds elute last (eluted by increasingly polar solvent).

  19. How does recrystallization purify a solid, and what solvent property is required?

    Recrystallization dissolves the impure solid in a minimum of hot solvent; on cooling, the pure compound crystallizes while impurities stay in solution. The ideal solvent dissolves the compound well when hot but poorly when cold.

  20. What information does each major spectroscopic region/technique provide: IR, 1H NMR, and mass spectrometry?

    IR identifies functional groups via bond vibrations. 1H NMR reveals the number, environment, and connectivity of hydrogens. Mass spectrometry gives molecular weight and fragmentation pattern (structural clues).

  21. What key IR absorption bands identify O-H, C=O, and N-H groups?

    O-H (alcohol): broad ~3200-3550 cm-1; O-H (carboxylic acid): very broad ~2500-3300 cm-1; N-H: ~3300-3500 cm-1 (one or two peaks); C=O: strong sharp ~1700-1750 cm-1.

  22. In 1H NMR, what do chemical shift, integration, and spin-spin splitting each tell you?

    Chemical shift (ppm) indicates the electronic environment (deshielding by electronegative/anisotropic groups). Integration gives the relative number of protons. Splitting (n+1 rule) indicates the number of neighboring nonequivalent protons.

  23. State the n+1 rule for NMR splitting and give the multiplicity for a proton next to 2 equivalent neighbors.

    A signal is split into (n+1) peaks, where n is the number of equivalent adjacent protons. Two equivalent neighbors give n+1 = 3, a triplet.

  24. What is the approximate 1H NMR chemical shift range for aromatic, vinyl, aldehyde, and carboxylic acid protons?

    Aromatic H: ~6.5-8.5 ppm; vinyl (C=C-H): ~4.5-6.5 ppm; aldehyde H (CHO): ~9-10 ppm; carboxylic acid H (COOH): ~10-12 ppm (broad).

  25. In mass spectrometry, what are the molecular ion peak (M+) and the base peak?

    The molecular ion peak (M+) corresponds to the intact molecule that has lost one electron; its m/z equals the molecular weight. The base peak is the most intense peak (set to 100% relative abundance), often a stable fragment.

  26. What does the M+2 peak pattern reveal in mass spectrometry for chlorine and bromine?

    An M+2 peak about one-third the height of M+ indicates chlorine (35Cl:37Cl ~ 3:1); an M+2 peak roughly equal to M+ indicates bromine (79Br:81Br ~ 1:1).

  27. What does UV-Vis spectroscopy detect, and what structural feature increases absorption wavelength?

    UV-Vis detects electronic transitions in molecules with conjugated pi systems (chromophores). Increasing conjugation lowers the HOMO-LUMO gap, shifting absorption to longer wavelengths (bathochromic/red shift).

  28. How is the degree of unsaturation (index of hydrogen deficiency) calculated and interpreted?

    For CcHhNnOoXx: DoU = (2c + 2 + n - h - x)/2. Each degree equals one ring or one pi bond; for example, a value of 4 commonly suggests a benzene ring (3 pi + 1 ring).

  29. In structure determination, why is 13C NMR a useful complement to 1H NMR?

    13C NMR shows the number of chemically distinct carbon environments and a wide chemical shift range (~0-220 ppm), helping identify carbon skeletons and carbonyl carbons (~160-220 ppm); it gives signals even for carbons bearing no hydrogens.

  30. How can melting point be used as a measure of purity?

    A pure compound has a sharp, narrow melting range close to its literature value. Impurities lower the melting point and broaden the range (melting-point depression), so a depressed/broad range signals impurity.

MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences FAQ

What is in the MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences syllabus?

MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences is split into 3 chapters: Structure, Bonding, and Stereochemistry, Reaction Mechanisms and Functional Group Chemistry and Separation, Purification, and Spectroscopy. Together they contain 10 topics and 24 sub-topics.

How many chapters are in MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences?

3 chapters, containing 10 topics and 24 sub-topics. The largest chapter is Reaction Mechanisms and Functional Group Chemistry, with 4 topics.

Are there flashcards for MCAT (Medical College Admission Test) Organic Chemistry for the Biological Sciences?

Yes — a 50-card Organic Chemistry for the Biological Sciences deck, printed in full in the flashcards section of this page and available in the Examius app with spaced repetition. The free plan covers one exam of your choice, including its flashcards; Examius Pro, a one-time purchase, unlocks every other exam and deck.