🇮🇳 GATE Petroleum Engineering · subject
GATE Petroleum Engineering Oil and Gas Well Testing Syllabus
The Oil and Gas Well Testing syllabus for GATE Petroleum Engineering in full: 12 chapters and 2 topics, every one listed below, plus 50 Oil and Gas Well Testing flashcards with answers.
Oil and Gas Well Testing syllabus: all 12 chapters
Expand any chapter to see its topics and sub-topics.
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Diffusivity Equation, Derivation & Solutions
1 topic- Radius of Investigation
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Principle of Superposition
overviewNo separate topics listed for this chapter.
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Horner’s Approximation
overviewNo separate topics listed for this chapter.
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Drill Stem Testing
overviewNo separate topics listed for this chapter.
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Pressure Transient Tests: Drawdown and Build Up-Test Analysis
1 topic- Wellbore Effects
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Multilayer Reservoirs
overviewNo separate topics listed for this chapter.
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Injection Well Testing
overviewNo separate topics listed for this chapter.
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Multiple Well Testing
overviewNo separate topics listed for this chapter.
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Interference Testing
overviewNo separate topics listed for this chapter.
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Pulse Testing
overviewNo separate topics listed for this chapter.
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Well-Test Analysis by Use of Type Curves
overviewNo separate topics listed for this chapter.
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Gas Well Testing
overviewNo separate topics listed for this chapter.
GATE Petroleum Engineering Oil and Gas Well Testing flashcards — 50 questions with answers
Define the radius of investigation in a well test.
It is the effective distance from the wellbore that a pressure transient has propagated into the reservoir at a given time, i.e. the radial distance reached by the pressure disturbance caused by changing the flow rate at the well.
Write the field-units equation for the radius of investigation $r_{inv}$.
$$r_{inv} = \sqrt{\frac{kt}{948\,\phi\mu c_t}}$$ with $r_{inv}$ in ft, $k$ in md, $t$ in hours, $\mu$ in cp, and $c_t$ in psi$^{-1}$.
How does the radius of investigation scale with flowing time $t$?
It scales with the square root of time, $r_{inv} \propto \sqrt{t}$, so doubling the radius requires roughly four times the test duration.
In the radius-of-investigation formula, how do permeability $k$ and porosity $\phi$ each affect $r_{inv}$?
$r_{inv}$ increases with permeability ($r_{inv}\propto\sqrt{k}$) and decreases with porosity ($r_{inv}\propto 1/\sqrt{\phi}$); higher $k$ lets the transient travel farther while higher $\phi$ slows its advance.
How does total compressibility $c_t$ and viscosity $\mu$ influence the radius of investigation?
$r_{inv}\propto \dfrac{1}{\sqrt{\mu c_t}}$, so higher viscosity or higher total compressibility both reduce the radius of investigation for a given time.
Why is the concept of radius of investigation important when planning a well test?
It tells how far into the reservoir the test 'sees', so it sets the minimum test duration needed to detect a boundary, fault, or pressure-support feature at a known distance, and defines the volume of reservoir characterized by the test.
Give the diffusivity-based proportional form of the radius of investigation.
$$r_{inv} \approx \sqrt{\frac{\eta t}{C}}, \qquad \eta = \frac{k}{\phi\mu c_t}$$ where $\eta$ is the hydraulic diffusivity and $C$ is a dimensionless constant ($\approx 948$ in field units when stated for $r_{inv}$).
What is the hydraulic diffusivity constant $\eta$ and its formula?
It governs how fast a pressure transient diffuses through the reservoir: $$\eta = \frac{k}{\phi\mu c_t}$$ Larger $\eta$ means faster pressure propagation and a larger radius of investigation.
A common rule expresses $r_{inv}$ using the dimensionless time. What is the relationship between $r_{inv}$ and time through $t_D$?
With $t_D = \dfrac{0.0002637\,k t}{\phi\mu c_t r_w^2}$, the transient reaches $r_{inv}$ when $t_D$ at that radius is about $0.25$ (i.e. $r_{inv}=2\sqrt{0.0002637\,kt/(\phi\mu c_t)}$ leads to the $948$ constant).
What is the drainage radius and how does it differ from the radius of investigation?
The drainage radius $r_e$ is the fixed outer boundary of the region a well ultimately drains under (pseudo)steady state, while the radius of investigation grows with time during the transient period until it reaches the boundaries; once boundaries are felt, $r_{inv}$ stops growing.
During infinite-acting radial flow, what assumption about boundaries is implied by the radius-of-investigation concept?
That no boundary has yet been reached: the pressure transient is still moving outward through an effectively infinite reservoir, so the response is governed only by reservoir/fluid properties and not by any limit.
How is the radius of investigation used to estimate the time to reach a known boundary at distance $L$?
Set $r_{inv}=L$ and solve for time: $$t = \frac{948\,\phi\mu c_t L^{2}}{k}$$ giving the approximate flow time before the boundary's effect appears in the pressure data.
Why does the radius of investigation NOT depend on flow rate $q$?
Because it describes how far the pressure disturbance has travelled (a function of the diffusion of pressure), which depends only on reservoir/fluid diffusivity and time; the rate $q$ controls the magnitude of the pressure change, not the speed of its propagation.
For a gas well, which parameter in $r_{inv}$ makes the radius of investigation strongly pressure-dependent?
Total compressibility $c_t$ (dominated by gas compressibility) and gas viscosity $\mu$ vary strongly with pressure, so $r_{inv}=\sqrt{kt/(948\phi\mu c_t)}$ must use pressure-evaluated (often pseudo-pressure/pseudo-time) values.
Define wellbore storage (afterflow).
It is the effect by which, after the surface rate is changed, the wellbore fluid itself continues to supply or absorb flow (by expansion/compression or changing liquid level) so the sand-face rate differs from the surface rate until the wellbore stabilizes.
Write the definition of the wellbore storage coefficient $C$.
$$C = \frac{\Delta V_{wb}}{\Delta p}$$ the change in volume of wellbore fluid per unit change in wellbore pressure, with units of bbl/psi (field) or m$^3$/Pa (SI).
Give the wellbore storage coefficient for a well controlled by fluid compression (single-phase wellbore).
$$C = V_{wb}\,c_{wb}$$ where $V_{wb}$ is the total wellbore fluid volume and $c_{wb}$ is the compressibility of the wellbore fluid.
Give the wellbore storage coefficient for a rising/falling liquid level in the wellbore.
$$C = \frac{144\,A_{wb}}{5.615\,\rho} = 25.65\,\frac{A_{wb}}{\rho}$$ where $A_{wb}$ is the cross-sectional area of the wellbore (ft$^2$) and $\rho$ is the fluid density (lbm/ft$^3$), giving $C$ in bbl/psi.
Define the dimensionless wellbore storage coefficient $C_D$ (field units).
$$C_D = \frac{0.8936\,C}{\phi\,c_t\,h\,r_w^{2}}$$ where $C$ is in bbl/psi, $h$ in ft, $r_w$ in ft, and $c_t$ in psi$^{-1}$.
What characteristic appears on a log-log plot of $\Delta p$ vs $\Delta t$ during pure wellbore storage?
A straight line of unit slope (slope = 1), because during storage-dominated flow $\Delta p$ is directly proportional to $\Delta t$.
Show the other 30 Oil and Gas Well Testing flashcards
During pure wellbore storage, what is the relationship between pressure change and time?
$$\Delta p = \frac{q B}{24\,C}\,\Delta t$$ pressure change is linear in time, which produces the unit-slope line on a log-log diagnostic plot.
How can the wellbore storage coefficient $C$ be obtained from the early unit-slope data?
From the unit-slope line, $$C = \frac{q B}{24}\,\frac{\Delta t}{\Delta p}$$ using any point $(\Delta t,\Delta p)$ on that line ($q$ in STB/D, $B$ in RB/STB, $\Delta t$ in hours, $\Delta p$ in psi).
On a pressure-derivative log-log plot, how does wellbore storage appear?
As an early-time hump where both the $\Delta p$ curve and the derivative curve overlie on a unit-slope line; the derivative then peaks and falls to the radial-flow stabilization (horizontal $0.5$ line).
Give an estimate for the time marking the end of wellbore-storage-dominated flow (start of radial flow).
$$t_{wbs} \approx \frac{(200000 + 12000\,s)\,C}{kh/\mu}$$ (hours), or in dimensionless form $t_D = (60 + 3.5\,s)\,C_D$.
Why must early-time data affected by wellbore storage be excluded from semilog (MTR) analysis?
Because storage masks the reservoir response: the sand-face rate is not equal to the surface rate, so the data do not lie on the true semilog straight line and would give wrong $k$ and skin if included.
Define the skin factor $s$.
A dimensionless number quantifying the additional (or reduced) pressure drop near the wellbore relative to the ideal reservoir flow; positive $s$ indicates damage (extra pressure loss) and negative $s$ indicates stimulation/improvement.
Write the equation for the additional pressure drop due to skin, $\Delta p_{skin}$.
$$\Delta p_{skin} = \frac{141.2\,q\mu B}{kh}\,s$$ with $q$ in STB/D, $\mu$ in cp, $B$ in RB/STB, $k$ in md, $h$ in ft.
How is the skin-related pressure drop expressed using the semilog slope $m$?
$$\Delta p_{skin} = 0.87\,m\,s$$ where $m$ is the absolute value of the slope of the semilog straight line (psi/cycle).
State the standard equation used to compute skin $s$ from a drawdown semilog analysis.
$$s = 1.151\left[\frac{p_{1hr}-p_{wf,0}}{m} - \log\!\left(\frac{k}{\phi\mu c_t r_w^{2}}\right) + 3.23\right]$$ where $p_{1hr}$ is read from the extrapolated semilog line at $\Delta t = 1$ hr.
What is the Hawkins formula for skin due to a damaged zone?
$$s = \left(\frac{k}{k_s} - 1\right)\ln\!\frac{r_s}{r_w}$$ where $k_s$ and $r_s$ are the permeability and radius of the altered (skin) zone.
According to Hawkins' formula, what sign of skin results when $k_s < k$ versus $k_s > k$?
When $k_s < k$ (damaged near-wellbore), $s>0$ (positive skin / damage); when $k_s > k$ (stimulated), $s<0$ (negative skin / improvement).
Define the effective (apparent) wellbore radius $r_{wa}$.
The radius of an ideal (zero-skin) well that would give the same pressure drop as the actual well with skin: $$r_{wa} = r_w\,e^{-s}$$
For a highly stimulated well, why can the effective wellbore radius be much larger than $r_w$?
Because a large negative skin makes $r_{wa}=r_w e^{-s}$ grow exponentially; e.g. $s=-5$ gives $r_{wa}\approx 148\,r_w$, modeling a fracture or acidized zone as an enlarged wellbore.
Define flow efficiency (FE) of a well.
The ratio of the actual productivity to the ideal (zero-skin) productivity: $$FE = \frac{\bar p - p_{wf} - \Delta p_{skin}}{\bar p - p_{wf}}$$ where $\bar p$ is average reservoir pressure.
What does a damage ratio (DR) greater than 1 indicate?
DR $= 1/FE$; a value greater than 1 indicates a damaged well (positive skin) producing less than its ideal potential, while DR $<1$ indicates a stimulated well.
List the main physical components that can contribute to total (apparent) skin.
Formation damage, partial penetration/limited entry, perforation effects, non-Darcy (turbulent) flow, deviation/inclination of the well, phase change/relative-permeability effects, and stimulation (fractures, acidizing) which contribute negative skin.
Distinguish mechanical (true) skin from pseudo-skin.
Mechanical skin is the rate-independent near-wellbore damage/stimulation (e.g. Hawkins damaged zone). Pseudo-skin is an apparent skin from geometry or flow effects (partial penetration, deviation, non-Darcy flow) that is not true formation alteration.
How is rate-dependent (non-Darcy) skin represented in the total skin?
$$s_{total} = s + D q$$ where $s$ is the constant mechanical skin and $D$ is the non-Darcy flow coefficient; $Dq$ grows with rate, common in high-rate gas wells.
How is the non-Darcy coefficient $D$ typically determined in the field?
By running multiple tests (or a multi-rate/multi-point test) at different rates and plotting apparent skin $s_{total}$ versus rate $q$; the slope gives $D$ and the intercept gives the true mechanical skin $s$.
What is partial penetration (limited entry) skin?
A positive pseudo-skin arising when only part of the producing interval is open to flow, forcing flow to converge vertically toward the open section, which adds extra pressure drop near the wellbore.
How does well deviation (inclination) affect skin?
An inclined or horizontal well increases the effective contact with the formation, contributing a negative pseudo-skin and improving productivity relative to a fully-penetrating vertical well.
Compare positive skin and negative skin in terms of well productivity.
Positive skin ($s>0$) means near-wellbore damage and extra pressure loss, lowering productivity; negative skin ($s<0$) means stimulation and reduced pressure loss, raising productivity. Zero skin is the ideal undamaged case.
In a pressure buildup test, how is skin computed from the Horner analysis?
$$s = 1.151\left[\frac{p_{1hr}-p_{wf}(\Delta t=0)}{m} - \log\!\left(\frac{k}{\phi\mu c_t r_w^{2}}\right) + 3.23\right]$$ with $m$ the slope of the Horner straight line and $p_{1hr}$ read from it at $\Delta t = 1$ hr.
Why does wellbore storage make skin determination unreliable if early data are misused?
Storage delays the appearance of the true semilog straight line; if the line is fit too early, the slope $m$ and $p_{1hr}$ are wrong, propagating into an erroneous skin value. The correct line must begin after storage ends.
What diagnostic feature on a log-log plot marks the transition from wellbore storage to infinite-acting radial flow?
The pressure-derivative curve leaves the early unit-slope hump and flattens to a horizontal stabilization at the value $0.5$ (dimensionless), indicating radial flow has begun.
How does increasing wellbore storage coefficient $C$ affect the duration of the storage period?
A larger $C$ (bigger wellbore volume or higher fluid compressibility) prolongs the storage-dominated period, delaying the start of interpretable radial flow and requiring a longer test.
Why does a positive skin lengthen the wellbore-storage-affected period?
Because the time to reach radial flow, $t_{wbs}\propto(200000+12000\,s)C$, increases with $s$; the extra near-wellbore pressure drop delays the establishment of the true semilog response.
What is the effect of skin on the productivity index (PI) of a well?
$$J = \frac{q}{\bar p - p_{wf}} = \frac{kh}{141.2\,\mu B\left[\ln(r_e/r_w) - 0.75 + s\right]}$$ positive $s$ raises the denominator and lowers $J$; negative $s$ raises $J$.
State the inflow (pseudosteady-state) equation showing where skin enters the flow rate expression.
$$q = \frac{kh(\bar p - p_{wf})}{141.2\,\mu B\left[\ln\frac{r_e}{r_w} - \frac{3}{4} + s\right]}$$ The skin $s$ adds to the geometric term, increasing total pressure drop for $s>0$.
Why is it important to separate wellbore-storage and skin effects when interpreting a well test?
Both distort the near-wellbore early-time response: storage controls the rate the formation sees, and skin adds a constant pressure offset. Misidentifying either leads to wrong permeability, wrong skin, and wrong productivity forecasts, so type-curve/derivative matching is used to deconvolve them.
GATE Petroleum Engineering Oil and Gas Well Testing FAQ
What is in the GATE Petroleum Engineering Oil and Gas Well Testing syllabus?
GATE Petroleum Engineering Oil and Gas Well Testing is split into 12 chapters: Diffusivity Equation, Derivation & Solutions, Principle of Superposition, Horner’s Approximation, Drill Stem Testing, Pressure Transient Tests: Drawdown and Build Up-Test Analysis, Multilayer Reservoirs, Injection Well Testing, Multiple Well Testing, Interference Testing, Pulse Testing, Well-Test Analysis by Use of Type Curves and Gas Well Testing. Together they contain 2 topics.
How many chapters are in GATE Petroleum Engineering Oil and Gas Well Testing?
12 chapters, containing 2 topics. The largest chapter is Diffusivity Equation, Derivation & Solutions, with 1 topic.
Are there flashcards for GATE Petroleum Engineering Oil and Gas Well Testing?
Yes — a 50-card Oil and Gas Well Testing deck, printed in full in the flashcards section of this page and available in the Examius app with spaced repetition. The free plan covers one exam of your choice, including its flashcards; Examius Pro, a one-time purchase, unlocks every other exam and deck.