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GATE Chemistry Inorganic Chemistry Syllabus
The Inorganic Chemistry syllabus for GATE Chemistry in full: 8 chapters, 63 topics and 38 sub-topics, every one listed below, plus 48 Inorganic Chemistry flashcards with answers.
Inorganic Chemistry syllabus: all 8 chapters
Expand any chapter to see its topics and sub-topics.
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Main Group Elements
21 topics- Hydrides
- Halides
- Oxides
- Oxoacids
- Nitrides
- Sulfides
- Shapes and reactivity
- Structure and bonding of boranes
- Carboranes
- Silicones
- Silicates
- Boron nitride
- Borazines
- Phosphazenes
- Allotropes of carbon
- Phosphorous and sulphur
- Industrial synthesis of compounds of main group elements
- Chemistry of noble gases
- Pseudohalogens
- Interhalogen compounds
- Acid-base concepts and principles
- Lewis
- Brønsted
- HSAB
- Acid-base catalysis
-
Transition Elements
6 topics- Coordination chemistry
- Structure and isomerism
- Theories of bonding
- VBT
- CFT
- MOT
- Energy level diagrams in various crystal fields
- CFSE
- Applications of CFT
- Jahn-Teller distortion
- Electronic spectra of transition metal complexes
- Spectroscopic term symbols
- Selection rules
- Orgel and Tanabe-Sugano diagrams
- Nephelauxetic effect
- Racah parameter
- Charge-transfer spectra
- Magnetic properties of transition metal complexes
- Ray-Dutt
- Bailar twists
- Reaction mechanisms
- Kinetic and thermodynamic stability
- Substitution and redox reactions
- Metal-metal multiple bond
- Coordination chemistry
-
Lanthanides and Actinides
1 topic- Recovery
-
Organometallics
7 topics- 18-Electron rule
- Metal-alkyl, metal-carbonyl, metal-olefin and metal-carbene complexes
- Metallocenes
- Fluxionality in organometallic complexes
- Types of organometallic reactions
- Homogeneous catalysis
- Hydrogenation
- Hydroformylation
- Acetic acid synthesis
- Metathesis
- Olefin oxidation
- Heterogeneous catalysis
- Fischer-Tropsch reaction
- Ziegler-Natta polymerization
-
Radioactivity
4 topics- Detection of radioactivity
- Decay processes
- Half-life of radioactive elements
- Fission and fusion processes
-
Bioinorganic Chemistry
5 topics- Ion transport
- Na+
- K+
- Oxygen binding, transport and utilization
- Electron transfer reactions
- Nitrogen fixation
- Metalloenzymes containing magnesium, molybdenum, iron, cobalt, copper and zinc
- Ion transport
-
Solids
10 topics- Crystal systems and lattices
- Miller planes
- Crystal packing
- Crystal defects
- Bragg’s law
- Ionic crystals
- Structures of AX, AX2, ABX3 type compounds
- Spinels
- Band theory
- Metals and semiconductors
-
Instrumental Methods of Analysis
9 topics- UV-visible, fluorescence and FTIR spectrophotometry
- NMR and ESR spectroscopy
- Mass spectrometry
- Atomic absorption spectroscopy
- Mössbauer spectroscopy
- Fe
- Sn
- X-ray crystallography
- Chromatography
- GC
- HPLC
- Electroanalytical methods
- Polarography
- Cyclic voltammetry
- Ion-selective electrodes
- Thermoanalytical methods
GATE Chemistry Inorganic Chemistry flashcards — 48 questions with answers
What is the general trend in the thermal stability of Group 14 hydrides $\ce{EH4}$ down the group?
Thermal stability decreases down the group: $\ce{CH4} > \ce{SiH4} > \ce{GeH4} > \ce{SnH4} > \ce{PbH4}$, because the $\ce{E-H}$ bond strength decreases as $E$ becomes larger and the orbital overlap with H worsens.
Classify hydrides into their three main types based on bonding, with an example of each.
Ionic (saline) hydrides — e.g. $\ce{NaH}$, $\ce{CaH2}$ (s-block, contain $\ce{H^-}$); Covalent (molecular) hydrides — e.g. $\ce{CH4}$, $\ce{NH3}$, $\ce{H2O}$ (p-block); Metallic (interstitial) hydrides — e.g. $\ce{PdH_{x}}$, $\ce{TiH2}$ (many d/f-block metals).
Why does $\ce{NH3}$ have a much higher boiling point than $\ce{PH3}$ despite N being smaller?
$\ce{NH3}$ engages in strong intermolecular hydrogen bonding (N is highly electronegative), whereas $\ce{PH3}$ shows only weak van der Waals interactions, so $\ce{NH3}$ boils much higher (−33 °C vs −88 °C).
How does the acidic strength of the hydrogen halides $\ce{HX}$ vary, and why?
Acid strength increases $\ce{HF} < \ce{HCl} < \ce{HBr} < \ce{HI}$. The dominant factor is the decreasing $\ce{H-X}$ bond dissociation energy down the group; $\ce{HF}$ is the weakest because of its strong bond and H-bonding.
What are the two general methods of classifying halides, and give an example of an electron-deficient halide.
Halides are classified as ionic (e.g. $\ce{NaCl}$), covalent (e.g. $\ce{CCl4}$), and polymeric/bridged. Electron-deficient halides include $\ce{BCl3}$ and $\ce{AlCl3}$ (which dimerizes to $\ce{Al2Cl6}$ with chlorine bridges).
Why is $\ce{CCl4}$ not hydrolyzed by water whereas $\ce{SiCl4}$ is readily hydrolyzed?
Carbon has no accessible d-orbitals and is sterically protected, so there is no low-energy pathway for nucleophilic attack. Silicon can expand its coordination number using vacant d-orbitals, allowing $\ce{H2O}$ attack: $\ce{SiCl4 + 2H2O -> SiO2 + 4HCl}$.
Distinguish between acidic, basic, amphoteric and neutral oxides with one example each.
Acidic — $\ce{SO3}$, $\ce{CO2}$ (form acids with water/react with bases); Basic — $\ce{Na2O}$, $\ce{CaO}$ (react with acids); Amphoteric — $\ce{Al2O3}$, $\ce{ZnO}$ (react with both); Neutral — $\ce{CO}$, $\ce{N2O}$, $\ce{NO}$.
How does the acidic/basic character of oxides change across a period and down a group?
Across a period (left to right) oxides change from basic → amphoteric → acidic as electronegativity rises. Down a group oxides become more basic (or less acidic) as metallic character increases.
Write the structures (shapes) of $\ce{SO2}$ and $\ce{SO3}$ in the gas phase.
$\ce{SO2}$ is bent (angular), V-shaped with a lone pair on S, bond angle $\approx 119^\circ$. Gaseous $\ce{SO3}$ is trigonal planar ($D_{3h}$), bond angle $120^\circ$.
For oxoacids of the same central element, how does acid strength vary with oxidation state? Illustrate with chlorine oxoacids.
Acid strength increases with the oxidation state of the central atom (more terminal O atoms stabilize the conjugate base): $\ce{HOCl} < \ce{HOClO} < \ce{HOClO2} < \ce{HOClO3}$, i.e. $\ce{HClO} < \ce{HClO2} < \ce{HClO3} < \ce{HClO4}$.
State Pauling's rule for estimating the strength of an oxoacid $\ce{(HO)_pXO_q}$.
For an oxoacid $\ce{(HO)_pXO_q}$, $pK_a \approx 8 - 5q$ where $q$ is the number of non-hydroxyl (terminal) oxygens. Each additional terminal O lowers $pK_a$ by about 5 units (stronger acid).
Compare the structures of phosphorous acid and phosphoric acid, and give their basicity.
Phosphorous acid $\ce{H3PO3}$ has structure $\ce{HP(O)(OH)2}$ — one P–H bond — and is dibasic (2 ionizable H). Phosphoric acid $\ce{H3PO4}$ is $\ce{OP(OH)3}$ — no P–H — and is tribasic.
What distinguishes covalent, ionic and interstitial nitrides? Give an example of each.
Ionic nitrides contain $\ce{N^{3-}}$, e.g. $\ce{Li3N}$, $\ce{Mg3N2}$ (s-block). Covalent nitrides, e.g. $\ce{BN}$, $\ce{Si3N4}$. Interstitial nitrides — hard, refractory d-block compounds, e.g. $\ce{TiN}$, $\ce{VN}$.
What is produced when an ionic nitride such as $\ce{Mg3N2}$ reacts with water?
Ionic nitrides hydrolyze to give ammonia and the metal hydroxide: $\ce{Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3}$.
Distinguish ionic, covalent (molecular) and metallic sulfides with an example of each.
Ionic sulfides contain $\ce{S^{2-}}$, e.g. $\ce{Na2S}$. Covalent/molecular sulfides, e.g. $\ce{CS2}$, $\ce{P4S3}$. Metallic/non-stoichiometric sulfides with metallic conduction, e.g. $\ce{FeS}$, $\ce{CoS}$. Many heavy-metal sulfides (e.g. $\ce{CuS}$, $\ce{HgS}$) are highly insoluble and covalent.
Using VSEPR, predict the shapes of $\ce{XeF2}$, $\ce{XeF4}$ and $\ce{XeF6}$.
$\ce{XeF2}$: linear (trigonal bipyramidal electron geometry, 3 lone pairs equatorial). $\ce{XeF4}$: square planar (octahedral, 2 axial lone pairs). $\ce{XeF6}$: distorted octahedral (capped octahedron) due to one lone pair in 7 electron domains.
Predict the shape and bond angle of $\ce{ClF3}$ using VSEPR.
$\ce{ClF3}$ is T-shaped: 5 electron domains (3 bonding + 2 lone pairs in a trigonal bipyramid, lone pairs equatorial). The F–Cl–F angles are slightly less than $90^\circ$ ($\approx 87.5^\circ$).
State Wade's rules for the structures of boranes ($n$ skeletal atoms) for closo, nido and arachno clusters.
Count skeletal electron pairs (SEP). $closo$: $n+1$ pairs (complete polyhedron). $nido$: $n+2$ pairs (one vertex missing). $arachno$: $n+3$ pairs (two vertices missing). For boranes, $\ce{B_nH_n^{2-}}$ closo, $\ce{B_nH_{n+4}}$ nido, $\ce{B_nH_{n+6}}$ arachno.
Describe the bonding in diborane $\ce{B2H6}$ and the nature of its bridging bonds.
$\ce{B2H6}$ has 4 terminal 2c–2e $\ce{B-H}$ bonds and 2 bridging three-center two-electron (3c–2e) $\ce{B-H-B}$ 'banana' bonds. Each B is roughly $sp^3$; the molecule is electron-deficient (only 12 valence electrons).
Using Wade's rules, classify $\ce{B5H9}$ and predict its structure.
$\ce{B5H9}$: skeletal electron pairs $= \tfrac{1}{2}(5\times2 + 9 - 5\times... )$. Standard count gives $n=5$, SEP $= n+2 = 7$ → nido. Structure is a square pyramid (octahedron missing one vertex).
Show the other 28 Inorganic Chemistry flashcards
What are carboranes, and what is the formula and shape of the most famous icosahedral carborane?
Carboranes are cluster compounds containing both carbon and boron (and hydrogen) in the cage. The classic example is closo-$\ce{C2B10H12}$ (dicarba-closo-dodecaborane), an icosahedral cage with 12 vertices; its $ortho$, $meta$, $para$ isomers differ in C positions.
How are the two carbon atoms of $\ce{C2B10H12}$ counted as skeletal electron donors in Wade's rules?
Each $\ce{CH}$ unit contributes 3 skeletal electrons (C has 4 valence e, minus 1 for the terminal C–H bond, giving 3), versus 2 for each $\ce{BH}$ unit. For $\ce{C2B10H12}$: $2(3)+10(2)=26 = 13$ pairs $= n+1$ ($n=12$) → closo.
What is the repeating backbone unit of silicones, and give the general formula of a linear polydimethylsiloxane.
Silicones (polysiloxanes) have an $\ce{-Si-O-Si-O-}$ backbone with organic groups on Si. Linear PDMS: $\ce{(CH3)3SiO[Si(CH3)2O]_nSi(CH3)3}$, built from $\ce{R2SiO}$ repeat units. They come from hydrolysis of $\ce{R2SiCl2}$.
How does the functionality of the chlorosilane (mono-, di-, tri-) determine silicone structure?
$\ce{R3SiCl}$ acts as a chain terminator (end caps), $\ce{R2SiCl2}$ gives linear chains, and $\ce{RSiCl3}$ gives cross-linked/network (3-D) silicones. Mixing ratios controls chain length and degree of cross-linking.
What is the fundamental structural building block of all silicates, and how do they link?
The basic unit is the $\ce{SiO4^{4-}}$ tetrahedron (Si at center, 4 O at corners). Tetrahedra link by sharing corner (bridging) oxygen atoms to form chains, rings, sheets, or 3-D frameworks.
Classify silicates by the number of shared corners: orthosilicate, pyrosilicate, cyclic/chain, sheet, and 3-D.
Orthosilicate $\ce{SiO4^{4-}}$ (0 shared O); Pyrosilicate $\ce{Si2O7^{6-}}$ (1 shared); Cyclic/single-chain $\ce{(SiO3^{2-})_n}$ (2 shared); Sheet/phyllosilicate $\ce{(Si2O5^{2-})_n}$ (3 shared); 3-D framework $\ce{SiO2}$ (4 shared, e.g. quartz, zeolites).
Boron nitride exists in two main forms analogous to carbon. Name them and their structures.
Hexagonal BN ('white graphite') — layered sheets of alternating B and N, soft lubricant, analogous to graphite (but layers eclipsed with B over N). Cubic BN (borazon) — sphalerite/diamond-like structure, extremely hard abrasive.
Why is hexagonal boron nitride an electrical insulator while graphite conducts?
In graphite the delocalized $\pi$ electrons are free to move, giving conduction. In h-BN the $\pi$ electrons are localized on the more electronegative nitrogen atoms (the B–N bond is polar, large band gap), so there are no mobile electrons — it is an insulator.
What is borazine, its formula, and why is it called 'inorganic benzene'?
Borazine is $\ce{B3N3H6}$, a six-membered planar ring of alternating B and N atoms each bearing one H, isoelectronic and isostructural with benzene ($\ce{C6H6}$). It has delocalized $\pi$ character, hence the nickname.
How is borazine synthesized, and how does its reactivity differ from benzene?
$\ce{3 B2H6 + 6 NH3 -> 2 B3N3H6 + 12 H2}$ (via the diammoniate/aminoborane intermediate). Unlike benzene, borazine readily undergoes addition reactions (e.g. with HCl across B–N bonds) because the ring is polar and less aromatic.
What are phosphazenes, give the general formula of the cyclic trimer, and how is it made?
Phosphazenes contain the $\ce{-N=P-}$ repeat unit. The cyclic trimer is hexachlorocyclotriphosphazene $\ce{(NPCl2)3}$, made by $\ce{n PCl5 + n NH4Cl -> (NPCl2)_n + 4n HCl}$.
What useful materials are obtained from cyclic chlorophosphazenes, and how?
Heating $\ce{(NPCl2)3}$ gives linear high polymer poly(dichlorophosphazene) $\ce{[NPCl2]_n}$ ('inorganic rubber'). Replacing the reactive Cl with $\ce{-OR}$ or $\ce{-OC6H5}$/$\ce{-OCH2CF3}$ groups yields stable polyphosphazene elastomers and fire-resistant materials.
Name the principal crystalline allotropes of carbon and the hybridization of carbon in each.
Diamond — $sp^3$, 3-D tetrahedral network (hardest, insulator). Graphite — $sp^2$, layered sheets (soft, conductor). Fullerenes (e.g. $\ce{C60}$) — $sp^2$ closed cages. Carbon nanotubes and graphene — $sp^2$ cylindrical/single-sheet forms.
Describe the structure of $\ce{C60}$ (buckminsterfullerene).
$\ce{C60}$ is a truncated icosahedron (soccer-ball) of 60 $sp^2$ carbons forming 20 hexagonal and 12 pentagonal faces. Each C is bonded to 3 others; it has 90 edges and the icosahedral $I_h$ symmetry.
Compare the structures of white, red and black phosphorus.
White phosphorus: discrete tetrahedral $\ce{P4}$ molecules (strained $60^\circ$ angles, very reactive, toxic). Red phosphorus: polymeric chains of linked $\ce{P4}$ units (amorphous, stable). Black phosphorus: layered, graphite-like puckered sheets (most thermodynamically stable, semiconductor).
Name the common allotropes of sulfur and the molecular unit of rhombic sulfur.
Rhombic ($\alpha$) and monoclinic ($\beta$) sulfur both consist of crown-shaped $\ce{S8}$ rings; rhombic is stable below $95.5\,^\circ\text{C}$. Plastic (amorphous) sulfur is made of long $\ce{S_n}$ chains formed by quenching molten sulfur.
Write the contact process for the industrial manufacture of sulfuric acid, including the key catalyzed step.
$\ce{S + O2 -> SO2}$; then the catalyzed step $\ce{2SO2 + O2 ->[V2O5] 2SO3}$; $\ce{SO3}$ is absorbed in $\ce{H2SO4}$ to give oleum $\ce{H2S2O7}$, then diluted: $\ce{H2S2O7 + H2O -> 2H2SO4}$.
Describe the Haber–Bosch process for ammonia, including conditions and catalyst.
$\ce{N2 + 3H2 <=> 2NH3}$, $\Delta H = -92\ \text{kJ mol}^{-1}$. Conditions: $\sim 200\ \text{atm}$, $\sim 400\text{–}450\,^\circ\text{C}$, finely divided iron catalyst (promoted with $\ce{K2O}$/$\ce{Al2O3}$). A compromise temperature balances rate and yield.
Outline the Ostwald process for nitric acid manufacture.
Catalytic oxidation of ammonia: $\ce{4NH3 + 5O2 ->[Pt/Rh] 4NO + 6H2O}$; then $\ce{2NO + O2 -> 2NO2}$; then $\ce{3NO2 + H2O -> 2HNO3 + NO}$ (the NO is recycled).
How is chlorine and sodium hydroxide produced industrially by the chlor-alkali (membrane) process?
Electrolysis of brine ($\ce{NaCl}$ solution): anode $\ce{2Cl^- -> Cl2 + 2e^-}$; cathode $\ce{2H2O + 2e^- -> H2 + 2OH^-}$. Net: $\ce{2NaCl + 2H2O -> Cl2 + H2 + 2NaOH}$; a cation-exchange membrane keeps products separated.
Describe the industrial preparation of phosphoric acid by the wet process and the thermal process.
Wet process: $\ce{Ca3(PO4)2 + 3H2SO4 -> 2H3PO4 + 3CaSO4}$. Thermal (furnace) process: burn elemental $\ce{P4}$ to $\ce{P4O10}$, then hydrate: $\ce{P4O10 + 6H2O -> 4H3PO4}$ (gives high-purity acid).
What was the first noble-gas compound prepared, by whom, and its formula?
$\ce{Xe+[PtF6]^-}$ (xenon hexafluoroplatinate), prepared by Neil Bartlett in 1962, after he noted that $\ce{O2}$ and $\ce{Xe}$ have similar first ionization energies and $\ce{PtF6}$ oxidized $\ce{O2}$.
Give the preparation conditions and products for $\ce{XeF2}$, $\ce{XeF4}$ and $\ce{XeF6}$.
Direct combination of $\ce{Xe}$ and $\ce{F2}$ at different ratios/conditions: low $\ce{F2}$ ratio → $\ce{XeF2}$ ($\ce{Xe + F2 -> XeF2}$); excess $\ce{F2}$, higher T/P → $\ce{XeF4}$ and $\ce{XeF6}$. Higher fluorine and pressure favor higher fluorides.
What are the products of complete and partial hydrolysis of $\ce{XeF6}$?
Partial hydrolysis: $\ce{XeF6 + H2O -> XeOF4 + 2HF}$; further $\ce{XeOF4 + H2O -> XeO2F2 ...}$; complete hydrolysis gives explosive xenon trioxide: $\ce{XeF6 + 3H2O -> XeO3 + 6HF}$.
Why do the noble gases form so few compounds, and why is Xe the most reactive of the stable ones?
They have stable, fully filled valence shells (very high ionization energies, near-zero electron affinity). Reactivity increases down the group as IE falls; Xe (and Kr to a lesser extent) has a low enough IE to be oxidized by very strong oxidizers like $\ce{F2}$ and $\ce{PtF6}$.
Compare the basicity/reducing nature trend of Group 15 hydrides $\ce{NH3}$ to $\ce{BiH3}$.
Basicity (lone-pair donor ability) decreases down the group: $\ce{NH3} > \ce{PH3} > \ce{AsH3} > \ce{SbH3} > \ce{BiH3}$, while reducing character and thermal instability increase down the group ($\ce{BiH3}$ is the strongest reductant, least stable).
What is the hybridization and shape of the silicate metasilicate chain anion, and how does asbestos relate to silicate structure?
Each Si is $sp^3$ in a $\ce{SiO4}$ tetrahedron sharing two corners to give single-chain pyroxenes $\ce{(SiO3^{2-})_n}$. Amphibole asbestos is a double-chain silicate $\ce{(Si4O11^{6-})_n}$; the fibrous chain structure gives its characteristic fibres.
State the structure and bonding type of $\ce{P4O10}$ and $\ce{P4O6}$.
Both derive from the $\ce{P4}$ tetrahedron. $\ce{P4O6}$ has an O atom bridging each of the 6 P–P edges (each P pyramidal). $\ce{P4O10}$ adds 4 terminal $\ce{P=O}$ oxygens (one per P), so each P is tetrahedrally bonded to 4 O. They are the anhydrides of $\ce{H3PO3}$ and $\ce{H3PO4}$ respectively.
GATE Chemistry Inorganic Chemistry FAQ
What is in the GATE Chemistry Inorganic Chemistry syllabus?
GATE Chemistry Inorganic Chemistry is split into 8 chapters: Main Group Elements, Transition Elements, Lanthanides and Actinides, Organometallics, Radioactivity, Bioinorganic Chemistry, Solids and Instrumental Methods of Analysis. Together they contain 63 topics and 38 sub-topics.
How many chapters are in GATE Chemistry Inorganic Chemistry?
8 chapters, containing 63 topics and 38 sub-topics. The largest chapter is Main Group Elements, with 21 topics.
Are there flashcards for GATE Chemistry Inorganic Chemistry?
Yes — a 48-card Inorganic Chemistry deck, printed in full in the flashcards section of this page and available in the Examius app with spaced repetition. The free plan covers one exam of your choice, including its flashcards; Examius Pro, a one-time purchase, unlocks every other exam and deck.