🇮🇳 GATE Chemical Engineering · subject
GATE Chemical Engineering Chemical Technology Syllabus
The Chemical Technology syllabus for GATE Chemical Engineering in full: 5 chapters and 14 topics, every one listed below, plus 49 Chemical Technology flashcards with answers.
Chemical Technology syllabus: all 5 chapters
Expand any chapter to see its topics and sub-topics.
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Inorganic chemical industries
3 topics- Sulfuric acid
- Phosphoric acid
- Chlor-alkali industry
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Fertilizers
4 topics- Ammonia
- Urea
- SSP (Single Super Phosphate)
- TSP (Triple Super Phosphate)
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Natural products industries
3 topics- Pulp and Paper
- Sugar
- Oil and Fats
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Petroleum refining and petrochemicals
overviewNo separate topics listed for this chapter.
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Polymerization industries
4 topics- Polyethylene
- Polypropylene
- PVC (Polyvinyl chloride)
- Polyester synthetic fibers
GATE Chemical Engineering Chemical Technology flashcards — 49 questions with answers
Which industrial process is used for the modern manufacture of sulfuric acid, and what is its key catalytic step?
The Contact process. Its key step is the catalytic oxidation of $\ce{SO2}$ to $\ce{SO3}$ over a vanadium pentoxide ($\ce{V2O5}$) catalyst: $\ce{2SO2 + O2 ->[V2O5] 2SO3}$.
In the Contact process, why is $\ce{SO3}$ absorbed in concentrated sulfuric acid to form oleum rather than directly in water?
Absorbing $\ce{SO3}$ directly in water is highly exothermic and produces a dense sulfuric acid mist (fog) that is hard to condense. Instead $\ce{SO3}$ is absorbed in $\approx 98\%$ $\ce{H2SO4}$ to form oleum: $\ce{SO3 + H2SO4 -> H2S2O7}$, which is then diluted.
Write the reaction by which oleum is converted to sulfuric acid, and give the formula of oleum (pyrosulfuric acid).
Oleum is $\ce{H2S2O7}$ (pyrosulfuric/disulfuric acid). $\ce{H2S2O7 + H2O -> 2H2SO4}$.
What does a Double Contact Double Absorption (DCDA) sulfuric acid plant achieve compared to a single absorption plant?
DCDA shifts the $\ce{SO2 -> SO3}$ equilibrium forward by removing $\ce{SO3}$ in an intermediate absorber before a second conversion pass, raising overall conversion to about $99.7\%$ and sharply cutting $\ce{SO2}$ emissions.
What is the optimum catalyst inlet temperature range for the $\ce{SO2}$ converter in the Contact process, and why not higher?
About $400$–$450\,^{\circ}\mathrm{C}$. The oxidation is exothermic, so although higher temperature speeds the rate, it lowers the equilibrium conversion (Le Chatelier); below $\sim 400\,^{\circ}\mathrm{C}$ the $\ce{V2O5}$ catalyst becomes inactive.
Name the two main commercial routes for manufacturing phosphoric acid and state which gives higher purity.
The wet process (acidulation of phosphate rock with $\ce{H2SO4}$) and the thermal/furnace process (combustion of elemental phosphorus). The thermal process gives higher-purity (food-grade) acid; the wet process is cheaper and dominant for fertilizers.
Write the principal reaction of the wet process for phosphoric acid and name the solid by-product.
$\ce{Ca5(PO4)3F + 5H2SO4 + 10H2O -> 3H3PO4 + 5CaSO4.2H2O + HF}$. The solid by-product is gypsum (phosphogypsum), $\ce{CaSO4.2H2O}$.
In the thermal (furnace) process for phosphoric acid, what two reactions occur after burning phosphorus?
Combustion: $\ce{P4 + 5O2 -> P4O10}$, then hydration: $\ce{P4O10 + 6H2O -> 4H3PO4}$.
What are the three principal products of the chlor-alkali industry, and from what feed are they made?
Chlorine ($\ce{Cl2}$), caustic soda / sodium hydroxide ($\ce{NaOH}$), and hydrogen ($\ce{H2}$), produced by electrolysis of aqueous sodium chloride (brine): $\ce{2NaCl + 2H2O -> 2NaOH + Cl2 + H2}$.
In a chlor-alkali cell, write the electrode half-reactions for chlorine and hydrogen evolution.
Anode: $\ce{2Cl- -> Cl2 + 2e-}$. Cathode: $\ce{2H2O + 2e- -> H2 + 2OH-}$.
Compare the three chlor-alkali cell technologies (mercury, diaphragm, membrane) on product purity and environmental concern.
Mercury cell: very pure, concentrated $\ce{NaOH}$ but uses toxic mercury. Diaphragm cell: lower NaOH purity (contains $\ce{NaCl}$), uses asbestos. Membrane cell: high-purity NaOH, lowest energy and most environmentally favorable; the modern standard.
Why must the anode and cathode compartments in a membrane chlor-alkali cell be separated?
To prevent $\ce{Cl2}$ and $\ce{NaOH/H2}$ from mixing (avoiding back-reaction to form $\ce{NaOCl}$ and explosive $\ce{H2}/\ce{Cl2}$ mixtures). The cation-exchange membrane lets only $\ce{Na+}$ pass to the cathode while blocking $\ce{Cl-}$ and $\ce{OH-}$.
Which process synthesizes ammonia industrially, and what are its typical operating temperature and pressure?
The Haber–Bosch process: $\ce{N2 + 3H2 <=> 2NH3}$, run at roughly $400$–$500\,^{\circ}\mathrm{C}$ and $150$–$300\ \text{atm}$ over a promoted iron catalyst.
Write the ammonia synthesis reaction with its enthalpy sign, and explain the choice of high pressure and moderate temperature.
$\ce{N2 + 3H2 <=> 2NH3},\ \Delta H < 0$ (exothermic). High pressure favors the side with fewer moles (forward), increasing yield; temperature is a compromise — high enough for an acceptable rate but not so high that the exothermic equilibrium yield collapses.
What catalyst is used in the Haber process and what are its common promoters?
Finely divided iron ($\ce{Fe}$, from magnetite) promoted with $\ce{K2O}$ (electronic promoter) and $\ce{Al2O3}$ (structural promoter that prevents sintering).
What is the principal industrial route for producing the hydrogen feed for ammonia synthesis?
Steam reforming of natural gas (methane): $\ce{CH4 + H2O -> CO + 3H2}$, followed by the water–gas shift reaction $\ce{CO + H2O -> CO2 + H2}$.
Write the two-step reaction scheme for the industrial synthesis of urea from ammonia and carbon dioxide.
Step 1 (carbamate formation, fast, exothermic): $\ce{2NH3 + CO2 -> NH2COONH4}$. Step 2 (dehydration, slow, endothermic): $\ce{NH2COONH4 -> NH2CONH2 + H2O}$.
Give the molecular formula and nitrogen content of urea, and state why it is a preferred nitrogen fertilizer.
Urea is $\ce{NH2CONH2}$ (molar mass $60\ \mathrm{g/mol}$) with about $46\%$ nitrogen by mass — the highest N content of any common solid nitrogenous fertilizer, making it economical to transport per unit N.
In urea manufacture, what is the role of the recycle (stripping) section, e.g. in total-recycle or stripping processes?
Because urea conversion per pass is incomplete (limited by carbamate equilibrium), unconverted $\ce{NH3}$ and $\ce{CO2}$ (as carbamate) are decomposed/stripped and recycled back to the reactor to improve overall conversion and reduce raw-material loss.
What is biuret in urea production, why is it undesirable, and how is its formation minimized?
Biuret, $\ce{NH2CONHCONH2}$, forms by condensation of two urea molecules ($\ce{2 urea -> biuret + NH3}$) at high temperature. It is toxic to crops, so it is kept low (typically $<1\%$) by limiting temperature and residence time during concentration/prilling.
Show the other 29 Chemical Technology flashcards
Define Single Super Phosphate (SSP), give its key reaction, and its typical available $\ce{P2O5}$ content.
SSP is made by treating phosphate rock with sulfuric acid: $\ce{Ca5(PO4)3F + 5H2SO4 -> ...}$ giving mainly monocalcium phosphate $\ce{Ca(H2PO4)2}$ plus gypsum. It contains roughly $16$–$20\%$ available $\ce{P2O5}$.
Write the simplified reaction for making SSP and identify why gypsum is present in the product.
$\ce{Ca3(PO4)2 + 2H2SO4 -> Ca(H2PO4)2 + 2CaSO4}$. The $\ce{CaSO4}$ (gypsum) forms because sulfuric acid converts excess calcium into calcium sulfate; it remains in SSP, diluting its $\ce{P2O5}$ content.
Define Triple Super Phosphate (TSP), give its manufacturing reaction, and its $\ce{P2O5}$ content.
TSP is made by treating phosphate rock with phosphoric acid (not sulfuric): $\ce{Ca3(PO4)2 + 4H3PO4 -> 3Ca(H2PO4)2}$. It contains about $44$–$48\%$ available $\ce{P2O5}$, roughly triple that of SSP.
Why does TSP have a much higher $\ce{P2O5}$ content than SSP despite both yielding monocalcium phosphate?
SSP is made with $\ce{H2SO4}$, which generates inert gypsum ($\ce{CaSO4}$) that dilutes the product. TSP is made with $\ce{H3PO4}$, which adds extra phosphate instead of sulfate, so no gypsum forms and the phosphate concentration is far higher.
Compare SSP and TSP on acid used, by-product, and approximate $\ce{P2O5}$ content.
SSP: uses $\ce{H2SO4}$, by-product gypsum ($\ce{CaSO4}$), $\sim 16$–$20\%$ $\ce{P2O5}$. TSP: uses $\ce{H3PO4}$, essentially no gypsum, $\sim 44$–$48\%$ $\ce{P2O5}$.
In pulp and paper manufacture, what is the purpose of pulping, and name the dominant chemical pulping process.
Pulping separates cellulose fibers from lignin and other wood components. The dominant chemical process is the Kraft (sulfate) process, which uses an alkaline 'white liquor' of $\ce{NaOH}$ and $\ce{Na2S}$.
What are the active chemicals in Kraft pulping white liquor, and what does the recovery boiler regenerate?
White liquor contains sodium hydroxide ($\ce{NaOH}$) and sodium sulfide ($\ce{Na2S}$). Spent black liquor is concentrated and burned in the recovery boiler; the smelt of $\ce{Na2CO3}$ and $\ce{Na2S}$ is causticized with lime to regenerate $\ce{NaOH}$.
Write the causticizing reaction used to regenerate $\ce{NaOH}$ in the Kraft recovery cycle.
$\ce{Na2CO3 + Ca(OH)2 -> 2NaOH + CaCO3}$. The $\ce{CaCO3}$ (lime mud) is calcined back to $\ce{CaO}$ in a lime kiln: $\ce{CaCO3 -> CaO + CO2}$.
Contrast the Kraft (sulfate) and sulfite pulping processes on liquor chemistry and fiber strength.
Kraft uses alkaline $\ce{NaOH}/\ce{Na2S}$ liquor, tolerates most wood species, and gives strong fibers with efficient chemical recovery. Sulfite uses acidic $\ce{H2SO3}$/bisulfite liquor, gives weaker but easily bleached pulp and is less common today.
What component of wood must be removed or degraded during pulping, and what is its rough mass fraction in wood?
Lignin, the amorphous polymer that binds cellulose fibers, makes up roughly $20$–$30\%$ of wood and must be dissolved/degraded so the cellulose fibers can be freed.
Outline the main unit operations in cane sugar manufacture from juice extraction to crystallization.
Milling/extraction of juice, clarification (liming and heating to remove impurities), evaporation to thick syrup, crystallization (boiling under vacuum to grow sugar crystals), and centrifugation to separate sugar crystals from molasses.
What is the role of the clarification (defecation) step with lime in sugar processing?
Lime ($\ce{Ca(OH)2}$) is added and the juice heated so that $\ce{CaO}$/phosphate forms a precipitate that adsorbs colloidal and suspended impurities, neutralizes acids (preventing sucrose inversion), and clarifies the juice before evaporation.
Define molasses in sugar manufacture and name a major use.
Molasses is the dark, viscous mother liquor remaining after sucrose crystals are removed by centrifugation and no further economic sugar can be crystallized. It is used for ethanol fermentation, cattle feed, and as a raw material for various fermentations.
Why is vacuum evaporation/boiling used in sugar concentration and crystallization?
Operating under vacuum lowers the boiling point so concentration occurs at reduced temperature, preventing thermal degradation and caramelization (inversion) of sucrose and saving energy via multiple-effect evaporators.
What chemical reaction underlies the hydrogenation of oils and fats, and what is its purpose?
Catalytic hydrogenation adds $\ce{H2}$ across the $\ce{C=C}$ double bonds of unsaturated fatty acid chains over a nickel catalyst, converting liquid oils to semi-solid fats (e.g., vanaspati/margarine) and improving oxidative stability.
Define the saponification of fats and write its general reaction.
Saponification is the alkaline hydrolysis of a triglyceride to produce soap and glycerol: $\ce{fat (triglyceride) + 3NaOH -> 3 R-COONa (soap) + glycerol}$.
What does the iodine value of an oil/fat measure, and what does a high value indicate?
The iodine value is the mass of iodine (in g) absorbed by $100\ \mathrm{g}$ of fat, measuring the degree of unsaturation ($\ce{C=C}$ bonds). A high iodine value indicates a highly unsaturated (drying/liquid) oil.
What is the saponification value of a fat and what does a high value imply about chain length?
The saponification value is the mg of $\ce{KOH}$ required to saponify $1\ \mathrm{g}$ of fat. A high saponification value implies low average molecular weight, i.e., shorter fatty-acid chains.
Name the two principal industrial methods of recovering oil from oilseeds.
Mechanical expression (expeller/screw pressing) and solvent extraction (typically with hexane), often used in sequence — pressing for high-oil seeds and solvent extraction to recover residual oil from the cake.
What monomer makes polyethylene, and how do LDPE and HDPE differ in structure and process?
Monomer: ethylene, $\ce{CH2=CH2}$. LDPE is highly branched, made by high-pressure free-radical polymerization, giving low density and crystallinity. HDPE is mostly linear, made at low pressure with Ziegler–Natta catalysts, giving higher density, crystallinity, and strength.
Write the polymerization of ethylene to polyethylene and classify the polymer.
$\ce{n\ CH2=CH2 -> [-CH2-CH2-]_n}$. Polyethylene is an addition (chain-growth) thermoplastic polymer.
What catalyst system enables low-pressure production of linear HDPE and stereoregular polypropylene?
Ziegler–Natta catalysts (e.g., $\ce{TiCl4}$ with an aluminium alkyl such as $\ce{Al(C2H5)3}$ as co-catalyst), which give stereoregular, linear polymers at low pressure.
What is the monomer for polypropylene, and why is tacticity important for it?
Monomer: propylene, $\ce{CH2=CH-CH3}$. Tacticity (spatial arrangement of the methyl groups) governs crystallinity: isotactic polypropylene is highly crystalline and useful, whereas atactic PP is soft and largely amorphous.
Define the three tacticities of polypropylene.
Isotactic: all methyl groups on the same side of the chain (highly crystalline). Syndiotactic: methyl groups alternate regularly side to side. Atactic: methyl groups randomly placed (amorphous, low value).
What is the monomer for PVC, and write the polymerization reaction.
Monomer: vinyl chloride, $\ce{CH2=CHCl}$. Polymerization: $\ce{n\ CH2=CHCl -> [-CH2-CHCl-]_n}$ (poly(vinyl chloride)), an addition thermoplastic.
Why are plasticizers added to PVC, and what is the difference between rigid and flexible PVC?
Plasticizers (e.g., phthalate esters like DOP) reduce intermolecular forces, lowering glass transition temperature to make PVC soft and flexible (used for cables, films). Rigid (unplasticized) PVC has little or no plasticizer and is used for pipes and window frames.
What is the dominant industrial route to the vinyl chloride monomer (VCM) for PVC?
Via ethylene: direct chlorination/oxychlorination of ethylene to 1,2-dichloroethane (EDC), $\ce{CH2=CH2 + Cl2 -> ClCH2CH2Cl}$, then thermal cracking (pyrolysis) of EDC: $\ce{ClCH2CH2Cl -> CH2=CHCl + HCl}$.
By what type of polymerization is polyester (PET) made, and write the monomers reacting.
PET is made by step-growth (condensation) polymerization of a diacid/diester and a diol: terephthalic acid (or dimethyl terephthalate) reacts with ethylene glycol, releasing water (or methanol). $\ce{HOOC-C6H4-COOH + HO-CH2CH2-OH -> [-OC-C6H4-CO-O-CH2CH2-O-]_n + H2O}$.
Classify polyester fiber (PET), polyethylene, and PVC as addition or condensation polymers and as thermoplastic or thermoset.
Polyethylene, polypropylene, and PVC are addition (chain-growth) thermoplastics. Polyester (PET) is a condensation (step-growth) thermoplastic. All four are thermoplastics (not thermosets).
GATE Chemical Engineering Chemical Technology FAQ
What is in the GATE Chemical Engineering Chemical Technology syllabus?
GATE Chemical Engineering Chemical Technology is split into 5 chapters: Inorganic chemical industries, Fertilizers, Natural products industries, Petroleum refining and petrochemicals and Polymerization industries. Together they contain 14 topics.
How many chapters are in GATE Chemical Engineering Chemical Technology?
5 chapters, containing 14 topics. The largest chapter is Fertilizers, with 4 topics.
Are there flashcards for GATE Chemical Engineering Chemical Technology?
Yes — a 49-card Chemical Technology deck, printed in full in the flashcards section of this page and available in the Examius app with spaced repetition. The free plan covers one exam of your choice, including its flashcards; Examius Pro, a one-time purchase, unlocks every other exam and deck.